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2 years ago

41. Consider the perimeter of the triangle shown. First, find the length of the hypotenuse.

Mathematics

2 answers:

Art [367]2 years ago

8 0

7^2+24^2=625
Square it and u get 25
So, therefore c is 25
if this helps mark as brainliest

marysya [2.9K]2 years ago

6 0

Use the Pythagorean theorem!

This principle applies to any right triangles.

This states the relationship between the sides that

(7)² + (24)² = x²

All you have to do is simplify at this point.

49 + 576 = x²

625 = x²

√ √

x = 25

You should try to memorize this right triangle. It can be very helpful in fast questionnaires, such as the SAT.

You might be interested in

Suppose that a random sample of 10 adults has a mean score of 62 on a standardized personality test, with a standard deviation o

aniked [119]

Answer:

The 90% confidence interval for the mean score of all takers of this test is between 59.92 and 64.08. The lower end is 59.92, and the upper end is 64.08.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.9}{2} = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.05 = 0.95$ , so $z = 1.645$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.645*\frac{4}{\sqrt{10}} = 2.08$

The lower end of the interval is the sample mean subtracted by M. So it is 62 - 2.08 = 59.92

The upper end of the interval is the sample mean added to M. So it is 62 + 2.08 = 64.08.

The 90% confidence interval for the mean score of all takers of this test is between 59.92 and 64.08. The lower end is 59.92, and the upper end is 64.08.

5 0

2 years ago

the boundary of a rectangular farm field in ireland has a straight rock wall along one side and fences along its other three sid

Inessa [10]

Answer:

781250 $ft^{2}$

Step-by-step explanation:

Let y is the length of the farm field

Let x is the width of the farm field

Given that, no fencing is necessary along the rock wall, so we can find the perimeter of the farm is:

2x + y = 2500 feet

<=> y = 2500 -2x

The are of the farm has the following formula:

A = x*y

<=> A = x(2500 - 2x)

<=> A = 2500x -2 $x^{2}$

To have the maximum area of field in square feet, we need to use differentials to estimate:

$\frac{dA}{dx}$ = 2500 - 4x

Set $\frac{dA}{dx}$ = 0, we have:

2500 - 4x = 0

<=> x = 625 feet.

=> y = 2500 - 2*625 = 1250 feet

So the maximum area of field is:

A = x*y = 625*1250 = 781250 $ft^{2}$

7 0

3 years ago

5000000000000000+ 100

Tasya [4]

Answer:

5000000000000100

Step-by-step explanation:

the question explains itself just ad 100

6 0

2 years ago

Question 1

Bess [88]

45c/100=9.25=37/4

c=20 5/9 (185/9)

4 0

2 years ago

A line passes through the points (-7, 2) and (1, 6).A second line passes through the points (-3, -5) and (2, 5).Will these two l

BlackZzzverrR [31]

Answer:

Yes, the lines intersect at (3,7). The solution is (3,7).

Explanation:

Step 1. The first line passes through the points:

(-7,2) and (1,6)

and the second line passes through the points:

(-3,-5) and (2,5)

Required: State if the lines intersect, and if so, find the solution.

Step 2. We need to find the slope of the lines.

Let m1 be the slope of the first line and m2 be the slope of the second line.

The formula to find a slope when given two points (x1,y1) and (x2,y2) is:

$m=\frac{y_2-y_1}{x_2-x_1}$

Using our two points for each line, their slopes are:

$\begin{gathered} m_1=\frac{6-2}{1-(-7)} \\ \\ m_2=\frac{5-(-5)}{2-(-3)} \end{gathered}$

The results are:

$\begin{gathered} m_1=\frac{6-2}{1-(-7)}=\frac{4}{1+7}=\frac{4}{8}=\frac{1}{2} \\ \\ \end{gathered}$ $m_2=\frac{5+5}{2+3}=\frac{10}{5}=2$

The slopes are not equal, this means that the lines are NOT parallel, and they will intersect at some point.

Step 3. To find the intersection point (the solution), we need to find the equation for the two lines.

Using the slope-point equation:

$y=m(x-x_1)+y_1$

Where m is the slope, and (x1,y1) is a point on the line.

For the first line m=1/2, and (x1,y1) is (-7,2). The equation is:

$y=\frac{1}{2}(x-(-7))+2$

Solving the operations:

$\begin{gathered} y=\frac{1}{2}(x+7)+2 \\ \downarrow\downarrow \\ y=\frac{1}{2}x+7/2+2 \\ \downarrow\downarrow \\ y=\frac{1}{2}x+5.5 \end{gathered}$

Step 4. We do the same for the second line. The slope is 2. and the point (x1,y1) is (-3, -5). The equation is:

$\begin{gathered} y=2(x-(-3))-5 \\ \downarrow\downarrow \\ y=2x+6-5 \\ \downarrow\downarrow \\ y=2x+1 \end{gathered}$

Step 5. The two equations are:

$\begin{gathered} y=\frac{1}{2}x+5.5 \\ y=2x+1 \end{gathered}$

Now we need to solve for x and y.

Step 6. Equal the two equations to each other:

$\frac{1}{2}x+5.5=2x+1$

And solve for x:

$\begin{gathered} \frac{1}{2}x+5.5=2x+1 \\ \downarrow\downarrow \\ 5.5-1=2x-\frac{1}{2}x \\ \downarrow\downarrow \\ 4.5=1.5x \\ \downarrow\downarrow \\ \frac{4.5}{1.5}=x \\ \downarrow\downarrow \\ \boxed{3=x} \end{gathered}$

Step 7. Use the second equation:

$y=2x+1$

and substitute the value of x to find the value of y:

$\begin{gathered} y=2(3)+1 \\ \downarrow\downarrow \\ y=6+1 \\ \downarrow\downarrow \\ \boxed{y=7} \end{gathered}$

The solution is x=3 and y=7, in the form (x,y) the solution is (3,7).

Answer:

Yes, the lines intersect at (3,7). The solution is (3,7).

6 0

1 year ago