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solniwko [45]
2 years ago
11

A school made $880 from ticket sales for the school play. From the ticket sales, $250 were from adult tickets.

Mathematics
2 answers:
Romashka-Z-Leto [24]2 years ago
5 0

Answer:

126

by-step explanation:

880 is that amount made in total.

250 were adults.

we can subtract that to simplify; 880-250= 630

Knowing that information we can assume the rest of the tickets are students.

5$ each.

5/620

How many 5s go into 630? 126.

Check your answer by multiplying 126 by 5, which = 630.

630+250=880.

Alecsey [184]2 years ago
3 0

Answer:

126 Students

Step-by-step explanation:

First, you subtract the money from the adult tickets from the total ($880), that leaves $630.

Since each student ticket is $5, you divide $630 by 5, which equals 126.

So, 126 students attended.

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Factor the expression 20k + 50
Yuliya22 [10]
Answer is 10(2k+5)

-----------------------------------

Work Shown:

20k+50 = 10*2k + 10*5
20k+50 = 10(2k+5)

Note how we can distribute the 10 back in to check our work
10(2k+5) = 10(2k)+10(5) = 20k+50
so that confirms we have the right answer

Another thing to notice is that 10 is the largest factor that we can pull out of 20k and 50. The value 10 is the GCF (greatest common factor) of 20 and 50.
4 0
3 years ago
An automobile manufacturer is considering using robots for part of its assembly process. Converting to robots is an expensive pr
LenKa [72]

Answer:

(a) The correct option is: <em>H₀</em>: <em>p</em> = 0.02 vs. <em>Hₐ</em>: <em>p</em> < 0.02.

(b) Explained below.

(c) The better value of <em>α</em> will be 0.10.

Step-by-step explanation:

An automobile manufacturer is considering using robots for part of its assembly process only if there is strong evidence that the proportion of defective installations is less for the robots than for human assemblers.

To test whether the proportion of defective installations is less for the robots than for human assemblers use a single-proportion <em>z</em>-test.

(a)

The hypothesis can be defined as:

<em>H₀</em>: The proportion of defective installations is same for both the robots and  human assemblers, i.e. <em>p</em> = 0.02.

<em>Hₐ</em>: The proportion of defective installations is less for the robots than for human assemblers, i.e. <em>p</em> < 0.02.

The alternate hypothesis is the claim or the statement that is being tested.

In this case we need to test whether the proportion of defective installations is less for the robots than for human assemblers or not, so that the manufacturer can decide whether they want to apply the conversion.

Thus, the correct option is:

<em>H₀</em>: <em>p</em> = 0.02 vs. <em>Hₐ</em>: <em>p</em> < 0.02.

(b)

A type I error occurs when we discard a true null hypothesis and a type II error is made when we fail to discard a false null hypothesis.

In this case a type I error will be committed if conclude that the proportion of defective installations is less for the robots than for human assemblers when in fact it is not.

And a type II error will be committed if we fail to conclude that proportion of defective installations is less for the robots than for human assemblers.

(c)

The power of the test is the probability of rejecting a false null hypothesis.

The power of the test sis affected by the significance level of the test (<em>α</em>).

Lesser the significance level of the test the lesser is the power of the test.

If the value of <em>α</em> is reduced from 0.05 to 0.01 then the region of acceptance will increase. This implies that there is low probability of rejecting the null hypothesis even when it is false.

So higher the value of <em>α</em> the higher is the probability of making a correct decision.

Thus, the better value of <em>α</em> will be 0.10.

3 0
3 years ago
A circle with circumference of 20 has an arc with a 72 degree central angle what is the length of the arc
FinnZ [79.3K]

Answer:

4

Step-by-step explanation:

3 0
3 years ago
Write an inequality and use substitution to solve the following problem:
nekit [7.7K]

They already spent $2000, and they only had $5100

Subtract

5100 - 2000 = 3100

$3,050 is your answer, because it is the only one that is less than 3100

hope this helps

7 0
3 years ago
Tony and Ricky spend a certain amount of money from their accounts each week at a pet shelter. The table shows the relationship
andriy [413]
<span>Function 1:

Number of Weeks (x)          Amount Remaining (dollars) (y)

1                                           30
2                                           24
3                                           18
4                                           12

You find the rate of weekley rate of change by calculating the difference of the amont remaing between two weeks:

24 - 30 = - 6

18 - 24  = - 6

12 - 18 = - 6

As you see the rate of change is constant: - 6 dollars per week. 


The equation shows the relationship between the amount of money, y, remaining in Ricky's account and the number of weeks, x:

Function 2: y = –7x + 30 Which statement states and explains which function shows a greater rate of change?

The rate of change is the slope of the linear function, and this is the coefficient of the independent variable, x. Then the rate of change is - 7 dollar per week. Now you know that the two rates are constant and that the second function shows a steeper decreasing.


</span>
7 0
3 years ago
Read 2 more answers
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