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3 years ago

What Is The Solution To This Equation? x/3 = 9PLEASE PLEASE HELP!

Mathematics

2 answers:

ziro4ka [17]3 years ago

7 0

The answer is 3. 3x3=9

k0ka [10]3 years ago

5 0

X=27 this is your answer

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2 years ago

Antonio moved boxes that weighed 26.5 pounds 34.2 pounds and 45.8 pounds. which is closest to number antonio moved all togehter

Andre45 [30]

B. 107 bc 26.5+34.2= 60.7+45.8= 106.5 round that to be 107.

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2 years ago

For the following amount at the given interest rate compounded continuously, find (a) the future value after 9 years, (b) the

Stella [2.4K]

Answer:

(a) The future value after 9 years is $7142.49.

(b) The effective rate is $r_E=4.759 \:{\%}$ .

(c) The time to reach $13,000 is 21.88 years.

Step-by-step explanation:

The definition of Continuous Compounding is

If a deposit of $P$ dollars is invested at a rate of interest $r$ compounded continuously for $t$ years, the compound amount is

$A=Pe^{rt}$

(a) From the information given

$P=4700$

$r=4.65\%=\frac{4.65}{100} =0.0465$

$t=9 \:years$

Applying the above formula we get that

$A=4700e^{0.0465\cdot 9}\\A=7142.49$

The future value after 9 years is $7142.49.

(b) The effective rate is given by

$r_E=e^r-1$

Therefore,

$r_E=e^{0.0465}-1=0.04759\\r_E=4.759 \:{\%}$

(c) To find the time to reach $13,000, we must solve the equation

$13000=4700e^{0.0465\cdot t}$

$4700e^{0.0465t}=13000\\\\\frac{4700e^{0.0465t}}{4700}=\frac{13000}{4700}\\\\e^{0.0465t}=\frac{130}{47}\\\\\ln \left(e^{0.0465t}\right)=\ln \left(\frac{130}{47}\right)\\\\0.0465t\ln \left(e\right)=\ln \left(\frac{130}{47}\right)\\\\0.0465t=\ln \left(\frac{130}{47}\right)\\\\t=\frac{\ln \left(\frac{130}{47}\right)}{0.0465}\approx21.88$

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2 years ago

Aubrey can run at a pace of six miles per hour. running at the same rate how many miles can she run in ninety minutes

Eddi Din [679]

Aubrey would be able to run 9 miles in ninety minutes.

90 minutes=1.5 hours

6*1.5=9

Hope this helps

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2 years ago

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lana66690 [7]

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2 years ago