Answer:
5(x+1) -2(y-3) = 0
Step-by-step explanation:
For a given line ax+by=c and point (h, k), a perpendicular line through the point can be written as ...
b(x-h) -a(y-k) = 0
A graphing calculator shows the point of intersection of the graphs of the two lines to be (x, y) = (-1, 3), so the line perpendicular to 2x+5y=5 through that point can be written ...
5(x+1) -2(y-3) = 0
_____
In the attached graph, the requested line is shown in black.
Answer:
3rd option
Step-by-step explanation:
Since the centre of dilatation is at the origin then multiply the coordinates by
K (- 3, 9 ) → K' (- 3( ), 9(
) ) → K' (- 1, 3 )
L (- 9, 0 ) → L' (- 9( ), 0 (
) ) → L' (- 3, 0 )
M (2, - 8 ) → M' (2 ( ), - 8 (
) ) → M' (
, -
)
N (6, 4 ) → N' (6 ( ) , 4 (
) ) → N' ( 2,
)
Answer:
csc(θ) = 1.1662
cos(θ) = 0.5145
Step-by-step explanation:
I attach the image of your question in the picture below
We know the values of the adjacent and opposite cathetus
tan(θ) = Opposite / Adjacent
tan(θ) = 5/3 = 1.666
θ = tan^-1 (5/3)
θ = 59.0362 °
Now that we have the angle, we can easily find the value of the expressions needed
csc(θ) = 1 / sin(θ) = 1/ (0.85749) = 1.1662
cos(θ) = 0.5145
