The mass of the piece of lead is calculated using the below formula
Q(heat)= mC delta T
Q = 78.0 j
M=mass =?
C=specific heat capacity ( 0.130 j/g/c
delat T=change in temperature = 9.0 c
by making M the subject of the formula
M = Q/ c delta T
M= 78.0 j/ 0.130 j/g/c x 9.0 c = 66.7 g of lead
Answer:
0.0305mol
Explanation:
CaCO3 ---> CaO + CO2
Mass of CaCO3 mol = 40 + 12 + (16 x 3) = 100g/mol
Number of CaCO3 moles heated = 3.05/100 = 0.0305 mol
One CaCO3 mol produces 1 mol CO2
Therefore 0.0305mol of CO2 produced.
The correct answer is:
2 atoms and 2 lone pairs; 2 atoms and 1 lone pair.
Both AX₂E₂ and AX₂E have different electron domain geometry; AX₂E₂ is tetrahedral and AX₂E is trigonal planar but both of them has the same molecular geometry
Bent
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H-H
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I think