Magnesium burns with oxygen to give magnesium oxide based on the following reaction:
2M<span>g</span>+<span>O<span>2 </span></span>........> 2Mg<span>O<span>(s)</span></span>+<span>energy
</span>From the periodic table:
molecular mass of magnesium = 24.3 grams
molecular mass of oxygen = 16 grams
From the reaction:
2 x 24.3 = 48.6 grams of magnesium are required to produce 2(24.3+16) = 80.6 grams of magnesium oxide.
We can know the amount of magnesium oxide produced from 8 grams of magnesium by simply doing cross multiplication as follows:
amount of magnesium oxide = (8 x 80.6) / 48.6 = 13.267 grams
Answer: Ag: 2.79x10^22 atoms
C atoms: 6.02x10^23 C atoms
Explanation:
5.0 grams of Ag is 0.0464 moles of Ag. (0.0464 moles)*(6.02x10^23 atoms/mole) = 2.79x10^22 atoms Ag
(0.50 moles)*(6.02x10^23 molecules/mole)*(2 C atoms/molecule) = 6.02x10^23 atoms of C
P 15 atm
V₁ = 12x103 m3 -3 3 V₁ = 12x10 m" T₁ = 25°c T= 28815 K
P₁ = 1.52x10 Pa
Now, Finel quantities, T₂ = 35°C = 308.15 °K
V2= 851 = -3 3
Now
by ideal gas equation
P2Y2 T2
= PV, T2
1152 X106 x 12x16 3 x 308115 8,5×103 x 288,15 = Pa
=
21294×10 Pa
P₂ = 21264 Atm
final
pressure will be
21264 Adm.
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The answer is B. The less mass then the less the gravity pulls on it
