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saul85 [17]
3 years ago
12

If 25.0 ml of seawater has a mass of 25.895 g and contains 1.295 g of solute, what is the mass/mass percent concentration of sol

ute in the seawater sample? 5.18% 5.001% 3.862% 96.5% 20.00%
Chemistry
1 answer:
Romashka-Z-Leto [24]3 years ago
8 0
The  %  mass/mass concentration  of   solute  in the  seawater  sample  is  calculated  as  below


% mass =  mass  of the  solute /mass of the solvent(sea water)  x100
mass  of  the  solute =1.295  g
mass  of the  solvent(sea   water_)  =  25.895 g

there  the % mass =  1.295/25.895  x100 =  5.001 %  
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