2 years ago

During STATIC ELECTRICITY to what type of objects & direction do electrons ALWAYS move to?

Chemistry

1 answer:

scZoUnD [109]2 years ago

3 0

Metal objects, electric objects, water,

You might be interested in

PLEASE HELP ITS VERY EASY FOR OTHER PLEASE ITS A TEST DUE IN AN HOUR PLEASEEEEEEEEEE

STatiana [176]

Answer:

I think it is three times I'm not sure

5 0

2 years ago

Read 2 more answers

How many moles of ag are formed by the complete reaction of 28.3 mol of pb?

levacccp [35]

Answer: 56.6 moles Explanation: 28.3 moles of Pb would produce twice as much moles as Ag. 28.3 X (2moles Ag/ 1 mol Pb) = 56.6 moles of Ag.

4 0

3 years ago

One gram of carbon contains 50,200,000,000,000,000,000,000 atoms. express the number of carbon atoms in scientific notation

german

N(C)=5,02·10²² atoms

calculation check:

N(C)=(1/12)*6.022*10²³=0.5018*10²³≈5.02·10²²

5 0

2 years ago

Using the picture below, once air mass A reaches location B, the weather conditions at location B will most likely become

olga2289 [7]

I think the answer is a

3 0

2 years ago

What is the energy released in this β − β − nuclear reaction 40 19 K → 40 20 C a + 0 − 1 e 19 40 K → 20 40 C a + − 1 0 e ? (The

Effectus [21]

Answer: The energy released in the given nuclear reaction is 1.3106 MeV.

Explanation:

For the given nuclear reaction:

$_{19}^{40}\textrm{K}\rightarrow _{20}^{40}\textrm{Ca}+_{-1}^{0}\textrm{e}$

We are given:

Mass of $_{19}^{40}\textrm{K}$ = 39.963998 u

Mass of $_{20}^{40}\textrm{Ca}$ = 39.962591 u

To calculate the mass defect, we use the equation:

$\Delta m=\text{Mass of reactants}-\text{Mass of products}$

Putting values in above equation, we get:

$\Delta m=(39.963998-39.962591)=0.001407u$

To calculate the energy released, we use the equation:

$E=\Delta mc^2\\E=(0.001407u)\times c^2$

$E=(0.001407u)\times (931.5MeV)$ (Conversion factor: $1u=931.5MeV/c^2$ )

$E=1.3106MeV$

Hence, the energy released in the given nuclear reaction is 1.3106 MeV.

6 0

2 years ago