Using the equation of the circle, it is found that since it reaches an identity, the point (√5, 12) is on the circle.
<h3>What is the equation of a circle?</h3>
The equation of a circle of center 
and radius r is given by:
In this problem, the circle is centered at the origin, hence 
.
The circle contains the point (-13,0), hence the radius is found as follows:
Hence the equation is:
Then, we test if point (√5, 12) is on the circle:
25 + 144 = 169
Which is an identity, hence point (√5, 12) is on the circle.
More can be learned about the equation of a circle at brainly.com/question/24307696
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Answer:
(a) two points
Step-by-step explanation:
The curve of a circle can only intersect another circle at a point or in an arc. The intersection will only be an arc if the circles have the same center and radius (are the same circle).
Different circles can only intersect each other at one or two points. Three different circles can intersect in one or two points. The 2-point case is shown in the attachment.
Answer:
4.................=y......
Remark
The formula for this series is
t_n = n^2 - 1
Explanation
If the series ends at 288, then the highest value n can have is 17
So you would write t_n = n^2 - 1 {n| 1 ≤ n ≤17}
If you said this to someone, you would say "t_n = n squared minus 1 where n is such that 1 is greater than or equal to 1 or less than or equal to 17"
Example
What is the 4th term in this series?
t_4 = 4^2 - 1
t_4 = 16 - 1
t_4 = 15
