Three circles can intersect in?
1 answer:
9514 1404 393
Answer:
(a) two points
Step-by-step explanation:
The curve of a circle can only intersect another circle at a point or in an arc. The intersection will only be an arc if the circles have the same center and radius (are the same circle).
Different circles can only intersect each other at one or two points. Three different circles can intersect in one or two points. The 2-point case is shown in the attachment.
You might be interested in
Triangle ABC is similar to triangle DEC, ∠B ≅ ∠E and 3DE = 2BC
<h3>What is transformation?</h3>Transformation is the movement of a point from its initial location to a new location. Types of transformation are <em>rotation, reflection, translation and dilation.</em>
Dilation is the increase or decrease in the size of a figure by a scale factor.
Right triangle ABC is reflected over AC, then dilated by a scale factor of 2/3 to form triangle DEC, hence:
Triangle ABC is similar to triangle DEC, corresponding angles are congruent (∠B ≅ ∠E) and DE = (2/3)BC i.e. 3DE = 2BC
Find out more on transformation at: brainly.com/question/4289712
#SPJ1
Hello!
6.
Since the area is that of a square, you know that all side lengths are the same.
Area is base times height (A = bh), but since base and height are the same for a square, you get the formula A = a².
The length of the side of a square with an area of 144 in² is 12 in.
7.
Rational number.
8.
This is a right triangle; use the Pythagorean Theorem to find missing lengths of right triangles. Pythagorean Theorem: a² + b² = c², where c is the hypotenuse of the triangle.
Plug in your leg lengths:
a² + b² = c²
8² + x² = 21²
64 + x² = 441
x² = 377
x = 19.4
6.
Since the area is that of a square, you know that all side lengths are the same.
Area is base times height (A = bh), but since base and height are the same for a square, you get the formula A = a².
The length of the side of a square with an area of 144 in² is 12 in.
7.
Rational number.
8.
This is a right triangle; use the Pythagorean Theorem to find missing lengths of right triangles. Pythagorean Theorem: a² + b² = c², where c is the hypotenuse of the triangle.
Plug in your leg lengths:
a² + b² = c²
8² + x² = 21²
64 + x² = 441
x² = 377
x = 19.4