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3 years ago

Can someone help me with this please? I don't know how to do it, and I need the answer asap ;-; (Image Below)

Mathematics

2 answers:

Ostrovityanka [42]3 years ago

7 0

There isn’t a picture

Marizza181 [45]3 years ago

4 0

Answer:

ma'am or sir... there is no picture attached... but whats the question?

Step-by-step explanation:

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Please help fast, I will mark BRAINLIEST 10. Find the rule. *

AURORKA [14]

Answer:

the answer to the question is y=x+2.

8 0

3 years ago

Hello Can Someone Please Answer This Math Question

Brrunno [24]

Answer:

200 in^2

Step-by-step explanation:

5•4+10•4+10•5=

200 in^2

i hope this helped you

3 0

3 years ago

$300 at 6% for 3 years

Charra [1.4K]

Its I=prt
so plug it in
I=300(.06)3 i got .06 because you have 6% you have to move the decimal the left twice 0.06 is what you get
now its basic multiplying
300 times .06 times 3
so it would be 54
I=$54
the balence you get from adding the P to the I so the balence would be 356
Bal=$356

7 0

3 years ago

Y=x+2;x=-3 solve each system by graphing step by step

ira [324]

I will solve for you right now.

7 0

3 years ago

Read 2 more answers

Help pleaseeeeeeeeeeeeeeeeeeeeeee

bixtya [17]

Answer: $\bold{(1)\ \dfrac{19,683}{64}\qquad (2)\ 16}$

<u>Step-by-step explanation:</u>

(1) (12, 18, 27, ...)

The common ratio is:

$r=\dfrac{a_{n+1}}{a_n}\quad r =\dfrac{18}{12}=\boxed{\dfrac{3}{2}}\quad \rightarrow \quad r=\dfrac{27}{18}=\boxed{\dfrac{3}{2}}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=12,\ r=\dfrac{3}{2}\\\\\\Equation:\\a_n =12\bigg(\dfrac{3}{2}\bigg)^{n-1}\\\\\\\\9th\ term:\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{9-1}\\\\\\a_9=12\bigg(\dfrac{3}{2}\bigg)^{8}\\\\\\.\quad =\large\boxed{\dfrac{19643}{64}}$

$(2)\qquad \bigg(\dfrac{1}{16},\dfrac{1}{8},\dfrac{1}{4},\dfrac{1}{2}\bigg)\\\\\\\text{The common ratio is}:\\\\r=\dfrac{a_{n+1}}{a_n}\quad r=\dfrac{\frac{1}{8}}{\frac{1}{16}}=\boxed{2}\quad \rightarrow \quad r=\dfrac{\frac{1}{4}}{\frac{1}{8}}=\boxed{2}$

The equation is:

$a_n=a_o(r)^{n-1}\\\\Given:a_o=\dfrac{1}{16},\ r=2\\\\\\Equation:\\a_n =\dfrac{1}{16}(2)^{n-1}\\\\\\\\9th\ term:\\a_9=\dfrac{1}{16}(2)^{9-1}\\\\\\a_9=\dfrac{1}{16}(2)^{8}\\\\\\.\quad =\large\boxed{16}$

3 0

3 years ago