First we will find the value of x.
To find the value of x we can add angle Q and angle O and set them equal to 180 and solve for x.
We will be setting them equal to 180 since the opposite angles of an inscribed quadrilateral are supplementary.
angle Q + angle O = 180
6x - 5 + x + 17 = 180
7x +12 = 180
7x = 168
x = 24
Now we can use 24 for x and find the value of angle QRO
angle QRO = 2x + 19
angle QRO = 2(24) + 19
angle QRO = 48 + 19
angle QRO = 67
So the answer choice B is the right answer.
Hope this helps :)<span />
Answer:
The slope is going to be 0.09
Step-by-step explanation:
Answer:
5
Step-by-step explanation:
thanks for the points
Answer:
A = √29
Step-by-step explanation:
The short of it is that ...
A² = 2² + 5² = 29
A = √29
_____
<u>Amplitude</u>
If you expand the second form using the sum-of-angles formula, you get ...
Asin(ωt +φ) = Asin(ωt)cos(φ) +Acos(ωt)sin(φ)
Comparing this to the first form, you find ...
c₂ = 2 = Acos(φ)
c₁ = 5 = Asin(φ)
The Pythagorean identity can be invoked to simplify the sum of squares:
(Asin(φ))² + (Acos(φ))² = A²(sin(φ)² +cos(φ)²) = A²·1 = A²
In terms of c₁ and c₂, this is ...
(c₁)² +(c₂)² = A²
A = √((c₁)² +(c₂)²) . . . . . . . formula for amplitude
_____
<u>Phase Shift</u>
We know that tan(φ) = sin(φ)/cos(φ) = (Asin(φ))/(Acos(φ)) = 5/2, so ...
φ = arctan(c₁/c₂) . . . . . . . formula for phase shift*
φ = arctan(5/2) ≈ 1.19029 radians
___
* remember that c₁ is the coefficient of the cosine term, and c₂ is the coefficient of the sine term.
Answer:
The one to the right
Step-by-step explanation:
