Answer:
B. It is reasonable to use the? z-interval procedure in this case? since, although the sample is small? (size less than? 15), the variable under consideration is very close to being normally distributed.
Step-by-step explanation:
answer b is considered to be correct because we know that the population is normal and the standard deviation is known, which allows using the interval z, the answer A is not correct because although the option to use the interval z is given, which is correct, the large sample is not favored, the answer C and D are incorrect because they both reject the use of the z interval and in d it is further rejected that although there is a normal distribution the sample is not, which is false
The answer is 0.4167 Hope that helped :)
Answer:
3:45 PM.
Step-by-step explanation:
We have been given that on Thursday afternoon at camp Alice played basketball and went swimming before dinner she spent 45 minutes playing basketball and one hour swimming dinner lasted for an hour. The dinner ended at 5:30 PM.
Since she spent 1 hour for swimming, so 1 hour before 5:30 PM would be 4:30 PM.
To find the time, when Alice started playing basketball, we need to find 45 minutes before 4:30 PM.
30 minutes before 4:30 PM would be 4:00 PM and 15 minutes before 4:00 PM would be 3:45 PM.
Therefore, Alice started playing basket ball at 3:45 PM.
Answer:
f(g(x)) = (5x)^2 = 25x^2
Step-by-step explanation:
If f(x) = x^2 and g(x) = 5x, then
f(g(x)) = (5x)^2 = 25x^2
Hmmm...I don't know what to tell you I can't type out your answer For you.
sorry
