Answer:
x = 2 ± 2 sqrt(5)i
Step-by-step explanation:
(x – 2)^2 + 20 = 0
Subtract 20 from each side
(x – 2)^2 + 20 -20=0 -20
(x – 2)^2 =- 20
Take the square root of each side
sqrt((x – 2)^2) =±sqrt(- 20)
x-2 = ±sqrt(- 20)
We know sqrt(ab) = sqrt(a) sqrt(b)
x-2 = ±sqrt(- 1) sqrt(20)
We know the sqrt (-1) = i
x-2 = ±i sqrt(4*5)
x-2 = ±i sqrt(4) sqrt(5)
Add 2 to each side
x-2+2 = 2 ±i sqrt(4) sqrt(5)
x = 2 ±i 2 sqrt(5)
x = 2 ± 2 sqrt(5)i
We can set up the width a X and, from the description the length would be 3X-1. The perimeter of a rectangle is determined by 2XL + 2Xw. Plugging into the equation 2(3X-1) + 2(X) = 118. Next distribute to get 6X-2 + 2X = 118. Combine like terms to get 8X = 120. Divide by 8 to get X = 15. The width is 15. The length is 3(15)-1 or 44. 88 +30 = 118
12 multiplied by 12 equals 144.
3terms = trinomial (7a^2, 4a, -12)
Degree of each term 2nd, 1st, constant
Largest degree: 2nd
Answer: 2nd degree trinomial
