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tangare [24]
3 years ago
9

(0, 4) (0, -6) No Solution Infinitely Many Solutions

Mathematics
1 answer:
xz_007 [3.2K]3 years ago
8 0

Answer:d

Step-by-step explanation:

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the answer is 90

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I used a calculator so-

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You have 19 digs for your current volleyball season. There are 5 games left in the season. You want to break your previous recor
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If log 3 = x and log 5 = y, express log 45 in terms of x and y.
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I believe that the answer is A

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2 years ago
A construction manager needs 12 workers to complete a building project in 54 days. Find in terms of T the number of workers need
ch4aika [34]

Answer:

<h3>2T/9</h3>

Step-by-step explanation:

A construction manager needs 12 workers to complete a building project in 54 days, we can write;

12 workers = 54 days

T find the number of workers needed to complete the same project in T days, we will write;

x workers = T days

Divide both equations

12/x = 54/T

Cross multiply

12T = 54x

x = 12T/54

x = 2T/9

Hence the number of workers needed to complete the same project in T days is 2T/9 workers

7 0
3 years ago
A certain population of mice is growing exponentially. After one month there are 48. After 2 months there are "192" mice. Write
REY [17]

Answer:

P(t) = 12e^1.3863k

Step-by-step explanation:

The general exponential equation is represented as;

P(t) = P0e^kt

P(t) is the population of the mice after t years

k is the constant

P0 is the initial population of the mice

t is the time in months

If after one month there are 48 population, then;

P(1) = P0e^k(1)

48 = P0e^k ...... 1

Also if after 2 months there are "192" mice, then;

192 = P0e^2k.... 2

Divide equation 2 by 1;

192/48 = P0e^2k/P0e^k

4 = e^2k-k

4 = e^k

Apply ln to both sides

ln4 = lne^k

k = ln4

k = 1.3863

Substitute e^k into equation 1 to get P0

From 1, 48 = P0e^k

48 = 4P0

P0 = 48/4

P0 = 12

Get the required equation by substituting k = 1.3863 and P0 = 12 into equation 1, we have;

P(t) = 12e^1.3863k

This gives the equation representing the scenario

8 0
3 years ago
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