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1 year ago

In the number 725.78, how does the value of the 7 in the tenths place compare to the value of the 7 in the hundreds place?

Mathematics

2 answers:

Vanyuwa [196]1 year ago

6 0

<h2>Answer:</h2>

C. 1/1,000

<h2>Step-by-step explanation</h2>

OleMash [197]1 year ago

3 0

Answer:

Step-by-step explanation:

which number has the least value

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I think its.......5/15=1/3

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iren2701 [21]

Answer:

3/2

Step-by-step explanation:

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2 years ago

What dose this equation equal ? -8x+4+(-3)=?

Marianna [84]

-8x+1 is the answer

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2 years ago

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0.25+(2.9 times 10^-3

gayaneshka [121]

Answer: .2529

Explanation:

1) 10^-3= .001

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3) .25+.0029= .2529

6 0

2 years ago

Read 2 more answers

Given segments AB and CD intersect at E.

nata0808 [166]

The length of a segment is the distance between its endpoints.

$\mathbf{AB = 3\sqrt{2}}$
AB and CD are not congruent
AB does not bisect CD
CD does not bisect AB

<u>(a) Length of AB</u>

We have:

$\mathbf{A = (1,2)}$

$\mathbf{B = (4,5)}$

The length of AB is calculated using the following distance formula

$\mathbf{AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

So, we have:

$\mathbf{AB = \sqrt{(1 - 4)^2 + (2 - 5)^2}}$

$\mathbf{AB = \sqrt{18}}$

Simplify

$\mathbf{AB = 3\sqrt{2}}$

<u>(b) Are AB and CD congruent</u>

First, we calculate the length of CD using:

$\mathbf{CD = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

Where:

$\mathbf{C = (2, 4)}$

$\mathbf{D = (2, 1)}$

So, we have:

$\mathbf{CD = \sqrt{(2 -2)^2 + (4 - 1)^2}}$

$\mathbf{CD = \sqrt{9}}$

$\mathbf{CD = 3}$

By comparison

$\mathbf{CD \ne AB}$

Hence, AB and CD are not congruent

<u>(c) AB bisects CD or not?</u>

If AB bisects CD, then:

$\mathbf{AB = \frac 12 \times CD}$

The above equation is not true, because:

$\mathbf{3\sqrt 2 \ne \frac 12 \times 3}$

Hence, AB does not bisect CD

<u>(d) CD bisects AB or not?</u>

If CD bisects AB, then:

$\mathbf{CD = \frac 12 \times AB}$

The above equation is not true, because:

$\mathbf{3 \ne \frac 12 \times 3\sqrt 2}$

Hence, CD does not bisect AB

Read more about lengths and bisections at:

brainly.com/question/20837270

7 0

2 years ago