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STatiana [176]
3 years ago
14

Can someone help me with this please . I’ll mark you as a brainliest.

Mathematics
1 answer:
Nina [5.8K]3 years ago
7 0

Step-by-step explanation:

hey ya go, mate anyways I switched to PC and I find these yw

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I will give the brainliest answer
GuDViN [60]

Answer:

82 {units}^{2}

Step-by-step

explanation

explanation is attached to the picture

hope this helps

brainliest appreciated

good luck! have a nice day!

3 0
3 years ago
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For the function f(x)=(7-8x)^2, find f^-1 determine whether f^-1 is a function
sertanlavr [38]
Is this question correct ?

5 0
3 years ago
A square pool has a side length of x feet.A uniform border around pool is 1 footwide.The total area of the pool and the border o
lions [1.4K]
The total area of pool and border = 361  square feet.

Length of square pool = x

Length of square pool plus border =  (x + 1 +1 ) = x + 2

There is 1 foot length on each side on the x  length.

The other length of the square pool and border =  (x + 2)

Area = (x+2)(x+2)

     (x + 2)(x +2) =  361.            Let A = x +2

        A*A = 361
            A²  = 361    Take square root of both sides
             A  = √361
               A = 19

A = x + 2 = 19
       x = 19 - 2
       x = 17

Area of square pool = x*x = 17*17 = 289

Area of the pool = 289 square feet.
8 0
3 years ago
How to find inequalities
geniusboy [140]

Answer:

Step 1 Eliminate fractions by multiplying all terms by the least common denominator of all fractions.

Step 2 Simplify by combining like terms on each side of the inequality.

Step 3 Add or subtract quantities to obtain the unknown on one side and the numbers on the other.

Hope that helped happy holidays!

6 0
3 years ago
If sin(theta) =4/5 and is in quadrant 2, the value of cot(theta
iren [92.7K]
\sin\theta= \frac{4}{5} 
\\
\\\sin^2\theta+\cos^2\theta=1
\\ \cos\theta=\pm \sqrt{1-\sin^2\theta} =\pm \sqrt{1-( \frac{4}{5})^2 } =\pm \sqrt{1- \frac{16}{25} } =\pm \sqrt{\frac{9}{25} }=\pm \frac{3}{5}}

\theta \in II \Rightarrow \cos\theta\ \textless \ 0 \Rightarrow \cos\theta=-\frac{3}{5}

\cot\theta= \frac{\cos\theta}{\sin\theta}= \frac{-\frac{3}{5}}{\frac{4}{5}}  =- \frac{3}{4}

5 0
3 years ago
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