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Masteriza [31]
3 years ago
6

A square pool has a side length of x feet.A uniform border around pool is 1 footwide.The total area of the pool and the border o

s 361 square feet.What is the area of the pool
Mathematics
1 answer:
lions [1.4K]3 years ago
8 0
The total area of pool and border = 361  square feet.

Length of square pool = x

Length of square pool plus border =  (x + 1 +1 ) = x + 2

There is 1 foot length on each side on the x  length.

The other length of the square pool and border =  (x + 2)

Area = (x+2)(x+2)

     (x + 2)(x +2) =  361.            Let A = x +2

        A*A = 361
            A²  = 361    Take square root of both sides
             A  = √361
               A = 19

A = x + 2 = 19
       x = 19 - 2
       x = 17

Area of square pool = x*x = 17*17 = 289

Area of the pool = 289 square feet.
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salantis [7]

Answer:

64

Step-by-step explanation:

surface area of the cube =96

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volume of the cube(V) =?

surface area = 6a^2    

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a ^2 =96/6  

a^2=16  

a = 4

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V= a^ 3  

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brainliest plz :'D

3 0
3 years ago
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Forty-seven percent of fish in a river are catfish. Imagine scooping out a simple random sample of 25 fish from the river and ob
WARRIOR [948]

Answer:

Therefore the correct option is a.) The standard deviation is 0.0998. The 10% condition is met because it is very likely there are more than 250 catfish in the river.

Step-by-step explanation:

i) Let p = 0.47

ii) therefore q = 1 - 0.47 = 0.53

iii) sample size, n =25

iii) standard deviation = \sqrt{\frac{p \times q}{n} }  = \sqrt{\frac{0.47 \times 0.53}{25} } = 0.0998

Therefore the correct option is

a.) The standard deviation is 0.0998. The 10% condition is met because it

    is very likely there are more than 250 catfish in the river.

8 0
3 years ago
The table shows the distance the students a group of students walked during after-school practice. What was the total distance,
ser-zykov [4K]

First let's convert the decimal numbers to mixed numbers:

\begin{gathered} 3.4=3+0.4=3+\frac{4}{10}=3+\frac{2}{5}=3\frac{2}{5} \\ 1.75=1+0.75=1+\frac{75}{100}=1+\frac{3}{4}=1\frac{3}{4} \\ 2.25=2+0.25=2+\frac{25}{100}=2+\frac{1}{4}=2\frac{1}{4} \end{gathered}

Now, adding all the numbers, we have:

\begin{gathered} (3+\frac{2}{5})+(3+\frac{1}{5})+(1+\frac{3}{4})+(2+\frac{1}{4})+(1+\frac{7}{10}) \\ =(3+3+1+2+1)+(\frac{2}{5}+\frac{1}{5}+\frac{3}{4}+\frac{1}{4}+\frac{7}{10}) \\ =10+(\frac{3}{5}+1+\frac{7}{10}) \\ =11+(\frac{6}{10}+\frac{7}{10}) \\ =11+\frac{13}{10} \\ =12+\frac{3}{10}=12\frac{3}{10} \end{gathered}

So the correct option is B.

8 0
1 year ago
How do you solve this do i need to plpug in the formula
Sergeeva-Olga [200]

Answer:

  B.  -2, 2

Step-by-step explanation:

Apparently, we're to presume that f(x) is the line that is graphed. It has a y-intercept of +1 and a slope (rise/run) of 1/2. Its equation is ...

  f(x) = 1/2x +1

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  1/2x +1 = √(x +2)

Squaring both sides, we get ...

  1/4x² +x + 1 = x +2

  1/4x² = 1 . . . . . . . . . . . . subtract x+1 from both sides

  x² -4 = 0 . . . . . . . . . . multiply by 4, subtract 4

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  x = -2, 2 . . . . . . . . . values of x that make the factors zero

The solutions to f(x) = g(x) are x = -2 and x = 2.

_____

<em>Additional comment</em>

The attached graph shows the x- and y-values at the points of intersection. The solutions to f(x) = g(x) are only the x-values, -2 and 2.

The square of (ax +b) is ...

  (ax +b)² = a²x² +2abx +b²

The point-slope equation of a line is ...

  y = mx + b . . . . . line with slope m and y-intercept b

3 0
3 years ago
the sum of nakias and tchallas age is 41 years. five years from now, the sum of their ages will be three times nakia's present a
Tresset [83]

Step-by-step explanation:

Nadia's is 41 years old.

8 0
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