The given two planes 2x + 4y + 3z = 5 and x + 8y + 10z = 3 are perpendicular to each other.
According to the given question.
We have two planes
2x - 4y + 3z = 5
and,
x + 8y + 10z = 3
Since, two planes are perpenicular if
Where 
, 
and 
and 
, 
and 
are the direction ratios of planes.
And the two planes are parallel to each other if
Here, the direction ratios of plane 2x + 4y + 3z = 5 are 2, -4, and 3 and the direction ratios of plane x + 8y + 10z = 3 are 1, 8, and 10
Now,
2(1) + (-4)(8) + 3(10)
= 2 - 32 + 30
= 0
Since, the sum of the product of the direction ratios of the two palnes is 0. Therefore, the given two planes 2x + 4y + 3z = 5 and x + 8y + 10z = 3 are perpendicular to each other.
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4ab x c/a + b = 4abc/a + b = 4bc + b = b ( 4c + 1 )
Answer:
Step-by-step explanation:
log(7)6+log(7)2^3
log(7)6+log(7)8
log(7)(8*6)
log(7)48 = > D is the correct answer.
Answer:
∠ACD= 109°
Step-by-step explanation:
∠A=38
180- ∠A= ∠B+C
180-38= 2∠B( ∠B=∠C) ( angles opposite to equal sides are equal)
142=2∠B
∠B=71
∠ACD=∠A+∠B ( exterior angle property)
∠ACD= 38+ 71= 109°
The coterminal angle for the -4π/5 are -14π/5 , 6π/5 and reference angle is π/5 respectively.
<h3>What is coterminal angles?</h3>
Two different angles that have the identical starting and ending edges termed coterminal angles however, since one angle measured clockwise and the other determined counterclockwise, the angles' terminal sides have completed distinct entire rotations.
We have an angle:
-4π/5
To find the coterminal angle, add and subtract by 2π in the angle -4π/5
Coterminal angle:
= -4π/5 - 2π
= -14π/5
= -4π/5 + 2π
= 6π/5
Reference angle:
= π - 4π/5 (as the angle lies in the second quadrant)
= π/5
Thus, the coterminal angle for the -4π/5 are -14π/5 , 6π/5 and reference angle is π/5 respectively.
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