Answer:
The rate charged by first mechanic per hour= x =$85
The rat charged by second mechanic per hour =y = $70
Step-by-step explanation:
Two mechanics worked on a car. The first mechanic worked for 10 hours, and the second mechanic worked for 15 hours. Together they charged a total of $1900. What was the rate charged per hour by each mechanic if the sum of the two rates was $155 per hour?
Solution
Let
x= hourly rate of the first mechanic
y= hourly rate of the second mechanic
Derive two equations to solve for the two unknowns
10x + 15y = 1900 (1)
x + y = 155 (2)
From (2)
x + y = 155
x=155-y
Substitute x=155-y into (1)
10x + 15y = 1900
10(155-y) + 15y =1900
1550 -10y + 15y =1900
5y =1900-1550
5y=350
Divide both sides by 5
y= 70
Substitute y=70 into (2)
x + y = 155
x + (70) =155
x=155 - 70
= 85
x= 85
The rate charged by first mechanic per hour= x =$85
The rat charged by second mechanic per hour =y = $70
Answer:
B. 14 ft
Step-by-step explanation:
I calculated it logically
G(x) = 3x² - 5x + 7
b) g(-2) ==> Substitude -2 into x
g(-2) = 3(-2)² - 5(-2) + 7
g(-2) = 12 + 10 + 7
g(-2) = 29
c) g(4) ==> Substitude 4 into x
g(4) = 3(4)² - 5(4) + 7
g(4) = 48 - 20 + 7
g(4) = 35
d) g(-x) ==> Substitude -x into x
g(-x) = 3(-x)² - 5(-x) + 7
g(-x) = -3x² + 5x + 7
e) g(1 - t) ==> Substitude 1 - t into x
g(1 - t) = 3(1 - t)² - 5(1 - t) + 7
g(1 - t) = 3(1 - 2t + t²) - 5 + 5t + 7
g(1 - t) = 3 - 6t + 3t² - 5 + 5t + 7
g(1 - t) = 3t² - t + 5
Can you post the image of the question?
So there for i can help
Answer:
36
Step-by-step explanation:
