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Anuta_ua [19.1K]
3 years ago
10

Critics are concerned about how easy it is to upload and download music on the Internet because:

Computers and Technology
2 answers:
evablogger [386]3 years ago
6 0
C. people have to buy entire albums, which can get expensive.
rjkz [21]3 years ago
3 0
A. Artists get paid by their managers when people buy tickets to a concert or people pay for the music. If you pirate music than you can be fined and charged for copyright violation
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no one can succeed in his or her career without relying on others for help or opportunities. It’s best, though,
fenix001 [56]

idk good luck man idek if this is a question but if it is just go with c or b

3 0
3 years ago
Which computer are used by mobile employees such as meter readers.​
Naily [24]

Answer:

Handheld/Mobile Computers

3 0
3 years ago
Read 2 more answers
PLS CAN ANYONE HELP ME
Nesterboy [21]

The exercise contains 15 questions. The solution is provided for each question.

Each question contains the necessary skills you need to learn.

I have added tips and required learning resources for each question, which helps you solve the exercise. When you complete each question, you get more familiar with a control structure, loops, string, and list.

Use Online Code Editor to solve exercise questions.

Also, try to solve the basic Python Quiz for beginners

Exercise 1: Given two integer numbers return their product. If the product is greater than 1000, then return their sum

Reference article for help:

Accept user input in Python

Calculate an Average in Python

Given 1:

number1 = 20

number2 = 30

Expected Output:

The result is 600

Given 2:

number1 = 40

number2 = 30

Expected Output:

The result is 70

Explanation:

4 0
2 years ago
Write a method transpose, that takes as argument a 2D array of integers, myTable, and returns the transpose of myTable. The tran
Gelneren [198K]

Answer:

The program to this question can be given as:

Program:

import java.util.*; //import package

public class Main //defining class

{

public static int[][] transpose(int[][] a1) //defining function transpose

{

int i,j; //define variables

int[][] transpose = new int[a1[0].length][a1.length]; //define variable transpose.

//loop for transpose matrix.

for(i = 0; i < a1.length; i++)  

{

for(j = 0; j < a1[i].length; j++)

{

transpose [j][i] = a1[i][j]; //hold value in transpose variable

}

}

return transpose ; //return transpose matrix.  

}

public static void main(String[] args) //main method.

{

int row,col,i,j; //defining variable.

Scanner obj = new Scanner(System.in); //creating Scanner class Object

System.out.print("Enter number of rows: ");//message

row = obj.nextInt(); //input rows form user.

System.out.print("Enter number of columns: ");//message

col = obj.nextInt(); //input columns form user.

int[][] a1 = new int[row][col]; //defining array.

System.out.println("Enter matrix"); //message

// loop for input array elements from user

for(i=0; i<a1.length;i++)  

{

for(j=0; j<a1[i].length;j++)  

{

a1[i][j]=obj.nextInt(); //input in array variable.

}

}

System.out.println("Matrix you insert :"); //message

// loop for display array.

for(i=0; i<a1.length;i++)  

{

for(j=0; j<a1[i].length;j++)  

{

System.out.print(a1[i][j]+" "); //print matrix

}

System.out.print("\n");

}

int[][] result = transpose(a1); //define result array variable that holds function value.

System.out.println("Transposed matrix is :");

//use loop for print Transpose matrix.

for(i = 0;i < result.length;i++)

{

for (j = 0; j < result[i].length;j++)

{

System.out.print(result[i][j] + " "); //print matrix

}

System.out.print("\n");

}

}

}

Output:

Enter number of rows: 2

Enter number of columns: 3

Enter matrix

2

3

4

9

8

7

Matrix you insert :

2 3 4  

9 8 7  

Transposed matrix is :

2 9  

3 8  

4 7  

Explanation:

The description of the above program can be given as:

  • In the above program firstly import a package, then declare a class that is "Main" inside a class defining a transpose() function this function returns a matrix in transpose form.
  • In the main class, we define a variable and matrix that is "row, col, i, j and a1[][]".  Then we Creating a scanner class object, which is used by row, col and a1[][] variables for user input.  
  • The row and col variables are used to declare matrix size and i, j variable is used in the loop for insert and display matrix.  
  • a1[][] matrix is used for input matrix elements and passes into transpose() function as an argument that returns a value that is held in the result variable. This is used as a loop for the print transpose matrix.

5 0
3 years ago
You are given an unsorted array x of elements that implement the Comparable interface. There are no duplicates in this array. Yo
Andrei [34K]

Answer:

boolean isEven = false;

if (x.length % 2 == 0)

isEven = true;

Comparable currentMax;

int currentMaxIndex;

for (int i = x.length - 1; i >= 1; i--)

{

currentMax = x[i];

currentMaxIndex = i;

for (int j = i - 1; j >= 0; j--)

{

if (((Comparable)currentMax).compareTo(x[j]) < 0)

{

currentMax = x[j];

currentMaxIndex = j;

}

}

x[currentMaxIndex] = x[i];

x[i] = currentMax;

}

Comparable a = null;

Comparable b = null;

if (isEven == true)

{

a = x[x.length/2];

b = x[(x.length/2) - 1];

if ((a).compareTo(b) > 0)

m = a;

else

m = b;

}

else

m = x[x.length/2];

8 0
3 years ago
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