Answer: 31
How: If there are two negative signs like this, you would connect them together and make it into a addition sign where you then can add them.
Answer:
A
Step-by-step explanation:
sqrt(x) ≤1
Square each side
x ≤1
But we have to look at the limit on the square root
We know that square root must be greater than or equal to zero so x ≥0
0 ≤x ≤1
To solve this, you need to substitute the value of Y into the equation 8X - Y = -12
So, since Y = 4, plug 4 in for Y:
8X - Y = -12
8X - (4) = -12
Now solve for X.
Does that help? Do you have any questions?
Just as a heads up this technique also works for larger equations. If Y = 3X, then you'd just plug 3X in for Y:
8X - Y = -12
8X - (3X) = -12
You got this!
