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Reika [66]
3 years ago
11

During a chemical reaction, calcium carbonate (CaCO3)

Chemistry
1 answer:
Misha Larkins [42]3 years ago
3 0
The answer should be A. CaO + CO2 —> CaCO3
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You are preparing some solutions for your instructor and have been asked to prepare 3.00 L of a 0.250M sodium hydroxide solution
grigory [225]

Answer:

C. 30.0 g NaOH and add water until the final solution has a volume of 3.00 L.

Explanation:

Molarity of a substance , is the number of moles present in a liter of solution .

M = n / V

M = molarity

V = volume of solution in liter ,

n = moles of solute ,

from the question ,

M =  0.250M

V  = 3.00 L

M = n / V

n = M * v

n = 0.250M * 3.00 L = 0.75 mol

Moles is denoted by given mass divided by the molecular mass ,

Hence ,

n = w / m

n = moles ,

w = given mass ,

m = molecular mass .

From the question ,

n = 0.75 mol NaOH

m = molecular mass of NaOH = 40 g/mol

n = w / m

w = n * m

w = 0.75 mol * 40 g/mol = 30.0 g

Hence , by using 30.0 g of NaOH and dissolving it to make up the volume to 3 L , a solution of 0.250 M can be prepared .

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Which identifies an oxidation-reduction reaction? a double replacement reaction a neutralization reaction a reaction in which ox
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A reaction in which oxidation numbers change is the answer! :D

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