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qwelly [4]
3 years ago
10

Write the chemical equation for hbro reacting with water. what are the products? do you expect to have any hbro molecules left i

n solution when the reaction is completed/reaches equilibrium?
Chemistry
2 answers:
pashok25 [27]3 years ago
8 0

Answer:

1. Reaction:

HBrO+H_2O-->H_3O^{+}+BrO^{-}

2. Yes, the solution will have HBrO molecules.

Explanation:

Hello,

In this case, the undergoing chemical reaction involving hypobromous acid and water yields both hypobromite and hydronium ions as shown below:

HBrO+H_2O-->H_3O^{+}+BrO^{-}

Now, since hypobromous acid's pKa is about 2x10⁻⁹, such value indicates that it is not completely dissociated in this reaction, therefore, there will be an amount of hypobromous acid molecules even when the equilibrium is attained.

Best regards.

Vinil7 [7]3 years ago
6 0
1) HOBr stands for hypobromous acid. On reacting with water, products formed are OBr- and H3O+. Following reaction occurs during this process.

<span>                                     HOBr + H2O </span>⇄<span> OBr- + H3O+

2) HOBr is a weak acid and have a lower value of dissociation constant (Ka ~ </span><span>2.3 X 10^–9). Hence, </span><span> large number of undissociated HOBr molecules are left in solution, when the reaction is completed/reaches equilibrium.</span>


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Why do single cell organisms divide?
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3 years ago
Dolomite is a mixed carbonate of calcium and magnesium. Calcium and magnesium carbonates both decompose upon heating to produce
Setler79 [48]

Answer:

72.03 %

Explanation:

Total mass of dolomite = 9.66 g

Let the mass of Magnesium carbonate = x g

The mass of calcium carbonate = 9.66 - x g

Calculation of the moles of Magnesium carbonate as:-

Molar mass of Magnesium carbonate = 122.44 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{x\ g}{84.3139\ g/mol}=\frac{x}{84.3139}\ mol

Calculation of the moles of calcium carbonate as:-

Molar mass of calcium carbonate = 100.0869 g/mol

Thus,

Moles= \frac{9.66 - x\ g}{100.0869\ g/mol}=\frac{9.66 - x}{100.0869}\ mol

According to the reaction shown below:-

MgCO_3\rightarrow MgO+CO_2

CaCO_3\rightarrow CaO+CO_2

In both the cases, the oxides formed from the carbonates in the 1:1 ratio.

So, Moles of MgO = \frac{x}{84.3139}\ mol

Molar mass of MgO = 40.3044 g/mol

Thus, Mass = Moles*Molar mass = \frac{x}{84.3139}\times 40.3044 \ g

Moles of CaO = \frac{9.66 - x}{100.0869}\ mol

Molar mass of CaO = 56.0774 g/mol

Thus, Mass = Moles*Molar mass = \frac{9.66 - x}{100.0869}\times 56.0774 \ g

Given that total mass of the oxide = 4.84 g

Thus,

\frac{x}{84.3139}\times 40.3044 +\frac{9.66 - x}{100.0869}\times 56.0774=4.84

\frac{40.3044x}{84.3139}+56.0774\times \frac{-x+9.66}{100.0869}=4.84

-694.1618435x+45673.48749\dots =40843.38968\dots

x=\frac{4830.09780\dots }{694.1618435}

x=6.9582

Thus, the mass of Magnesium carbonate = 6.9582 g

\%\ mass=\frac{Mass_{MgCO_3}}{Total\ mass}\times 100

\%\ mass=\frac{6.9582}{9.66}\times 100=72.03\ \%

3 0
3 years ago
2. What is the electron configuration of an electrically neutral atom of magnesium?
alekssr [168]
Are u talking about electron sublevel config or where the electrons show in the "rings" of the atom
7 0
3 years ago
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