In this case, the undergoing chemical reaction involving hypobromous acid and water yields both hypobromite and hydronium ions as shown below:
Now, since hypobromous acid's pKa is about 2x10⁻⁹, such value indicates that it is not completely dissociated in this reaction, therefore, there will be an amount of hypobromous acid molecules even when the equilibrium is attained.
1) HOBr stands for hypobromous acid. On reacting with water, products formed are OBr- and H3O+. Following reaction occurs during this process.
<span> HOBr + H2O </span>⇄<span> OBr- + H3O+
2) HOBr is a weak acid and have a lower value of dissociation constant (Ka ~ </span><span>2.3 X 10^–9). Hence, </span><span> large number of undissociated HOBr molecules are left in solution, when the reaction is completed/reaches equilibrium.</span>
Because iodine is a liquid, it has no melting point. Iodine is not an electrical conductor because each molecule consists of two iodine atoms connected by a covalent bond that cannot be stimulated sufficiently to transmit electrical energy.