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KATRIN_1 [288]
4 years ago
8

Which identifies an oxidation-reduction reaction? a double replacement reaction a neutralization reaction a reaction in which ox

idation numbers change a reaction in which no electrons are transferred
Chemistry
2 answers:
OLga [1]4 years ago
7 0

A reaction in which oxidation numbers change is the answer! :D

☆ Dont forget to mark brainliest ☆

Dahasolnce [82]4 years ago
5 0

Answer: Option (c) is the correct answer.

Explanation:

In an oxidation reaction there is loss of electrons whereas in a reduction reaction there is gain of electrons.

So, overall there is exchange of electrons in an oxidation-reduction reaction.

For example, CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O is an oxidation-reduction reaction.

As there is change in oxidation number of oxygen from 0 to -2 and change in oxidation number of carbon from -4 to +4.

Thus, we can conclude that a reaction in which oxidation numbers change identifies an oxidation-reduction reaction.

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What is the minimum frequency of light required to observe the photoelectric effect on pd
Tems11 [23]

Answer:

1.26 × 10¹⁵ s⁻¹

Explanation:

Work function is the minimum energy required to remove an electron from the surface of metal

energy of the electron = hf - Φ

Φ = work function = hf₀ where f₀  = threshold frequency

f₀ = Φ / h  where h ( Planck constant = 6.626 × 10⁻³⁴ Js)

Φ = 5.22eV = 5.22 × 1 eV  where 1 eV = 1.60217662 × 10⁻¹⁹ J

Φ = 5.22 × 1.60217662 × 10⁻19 J = 8.363362 × 10⁻¹⁹ J

f₀ =  (8.363362 ×10⁻¹⁹  J) / (6.626× 10⁻³⁴ Js) = 1.26 × 10¹⁵ s⁻¹

The frequency must be greater than the 1.26 × 10¹⁵ s⁻¹ to observe the emission

3 0
4 years ago
Explain the regiochemistry of the Friedel-Crafts alkylation of 1,4-dimethoxybenzene. There are three positions available for the
defon

Answer:

In an electrophilic aromatic substitution (Friedel Crafts alkylation) first in the monoalkylation of the 1,4-dimethoxybenzenethe the methoxy groups redirects the substitution for ortho-para positions with respect to the electrophile that is going to enter (alkyl group) this is due to the increase in electron density in that position, that is , to the inductive effect.

According to the second incoming alkyl group there would be 3 positions available, from which it will choose the meta position in relation to the second methoxy group, since the alkyl group is a weak activator of the ortho meta positions and coincides with the position to which it redirects the second methoxy group.

7 0
3 years ago
What is the molality of a solution containing 10.0 G of NA2 S04 and 1000.0 G of water
galina1969 [7]

Explanation:

1 literThe total of water is equal to 1000.0 g of water

we need to find the molality of a solution containing 10.0 g of dissolved in  Na₂S0₄1000.0 g of water

1. For that find the molar mass

Na:  2 x 22.99= 45.98

S:  32.07

O:  4 x 16= 64

The total molar mass is 142.05

We have to find the number of moles, y

To find the number of moles divide 10.0g by 142.05 g/mol.

So the number of moles is 0.0704 moles.

For the molarity, you need the number of moles divided by the volume. So, 0.0704 mol/1 L.

The molarity would end up being 0.0704 M

The molality of a solution containing 10.0 g of Na2SO4 dissolved in 1000.0 g of water is  0.0704 Mliter

7 0
3 years ago
Would isotopes of the same element have the same number of electrons?
posledela
No, isotopes would have a different number of electrons
8 0
3 years ago
If a seed grows well in a very salty environment then that seed has a high salt tolerance.
garik1379 [7]
That answer is true
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3 years ago
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