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2 years ago

6

Nequalities in Non Standard Form

1 answer:

Dominik [7]2 years ago

7 0

Answer:

x < 31 I think

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I don't know what to do

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3 years ago

Find f (0) if f(t) = t2 – 2t – 5.

Sonbull [250]

Answer is -5.

Explanation- Since t equals 0. You put 0 in place of every t.

0(2)- 2(0)- 5 =
0-0-5= -5

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2 years ago

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Use the Quadratic Formula to Solve: <br> 8x^2+4x-16= -x^2

Harlamova29_29 [7]

Solve the equation for x by finding a, b and c of the quadratic then applying the quadratic formula

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2 years ago

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s). Complete the st

Zina [86]

Question:

If cos(θ) =-8/17 and sin(θ) is negative, then sin(θ) = ___ and tan(θ) =___.

Answer:

$Sin\theta = \frac{-15}{17}$

$Tan\theta = \frac{15}{8}$

Step-by-step explanation:

Given

cos(θ) =-8/17

Required

sin(θ) = __

tan(θ) =__

The first step is to determine the length of the third side

Given that

$cos(\theta) = \frac{Adj}{Hyp}$

Where Adj and Hyp represent Adjacent and Hypotenuse

$cos(\theta) = \frac{-8}{17}$

By comparison

$Adj = -8\ and\ Hyp = 17$

Using Pythagoras

$Hyp^2 = Adj^2 + Opp^2$

By Substitution

$17^2 = (-8)^2 + Opp^2$

$289 = 64 + Opp^2$

Subtract 64 from both sides

$289 - 64 = 64 - 64 + Opp^2$

$225 = Opp^2$

Take square roots of both sides

$\sqrt{225} = \sqrt{Opp^2}$

$\sqrt{225} = Opp$

$15 = Opp$

$Opp = 15$

The question says that sin(θ) is negative; This implies that θ is in the third quadrant and as such

$Opp = -15$

From trigonometry

$Sin\theta = \frac{Opp}{Hyp}$

$Sin\theta = \frac{-15}{17}$

Also from trigonometry

$Tan\theta = Sin\theta / Cos\theta$

$Tan\theta = \frac{-15}{17} / \frac{-8}{17}$

$Tan\theta = \frac{-15}{17} * \frac{-17}{8}$

$Tan\theta = \frac{-15 * -17}{17 * 8}$

$Tan\theta = \frac{15 * 17}{17 * 8}$

$Tan\theta = \frac{15}{8}$

5 0

2 years ago

Find the value of x.<br> B<br> 6<br> 8<br> А<br> х<br> D<br> x = [?]

Keith_Richards [23]

Answer:

What's the question is that a good thing

5 0

2 years ago