By completing the square: x²-8x+19 = (x-4)²-16+19 = (x-4)²+3 so minimum point = (4,3)
By calculus: f'(x) = 2x-8. (minimum point occurs when f'(x)=0 therefore)
2x-8 = 0 means x=4 and the corresponding y value is 3.
The minimum value of this function (y) is 3 and this occurs when x = 4.
Answer:
Step-by-step explanation:
(2u+3u)(u+v)-2u+3v
=2u(u+v)+3u(u+v)-2u+3v
=2u^2+2uv+3u^2+3uv-2u+3v
=5u^2+5uv-2u+3v
Answer:
<u>13/15 </u>
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Decimal Form: 0.86
Not sure if you would've preferred a step-by-step solution. Sorry! Hope you find this helpful, good luck!
Answer:
12 minutes
Step-by-step explanation:
So, he spent 12 minutes jogging.
