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Illusion [34]
3 years ago
14

Mary and roberto bought identical backpacks at different stores. marys backpacks originally cost $65 and was discounted 25%. rob

ertos backpack orignally cost $75 and was on sale for 30% off the original price.which backpack was a better buy?
Mathematics
1 answer:
garri49 [273]3 years ago
6 0
Mary's backpack: 25% of 65 = 0.25 * 65 = 16.25; 65 - 16.25 = $48.75
Roberto's backpack: 30% of 75 = 0.3 * 75 = 22.5; 75 - 22.5 = $52.5

Mary's backpack was a better buy because it was cheaper. 
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PLEASE HELP FAST !!<br> 3/2+19/3
yan [13]

Answer:

28/6 yeah thats right wasp

5 0
3 years ago
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Find the GCF of <img src="https://tex.z-dn.net/?f=18x%5E%7B3%7D" id="TexFormula1" title="18x^{3}" alt="18x^{3}" align="absmiddle
melamori03 [73]

18x^3 = 6x^3 *  1

30x^5 = 6x^3 * 5x^2


So GCF = 6x^3


Answer

6x^3

8 0
3 years ago
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10 pt
lord [1]

Answer:

C. 434π

Step-by-step explanation:

Given:

Radius (r) = 7 in.

Height (h) = 24 in.

Required:

Surface area of the cylinder

Solution:

S.A = 2πrh + 2πr²

Plug in the values

S.A = 2*π*7*24 + 2*π*7²

S.A = 336π + 98π

S.A = 434π

5 0
3 years ago
A group of 86 people consist of men women and children. There are twice as many women then there are men. There are 6 more child
weqwewe [10]

Answer: 16 men

32 women

38 children

Step-by-step explanation:

Let x represent the number of men in the group.

Let y represent the number if women in the group.

Let z represent the number of children in the group.

A group of 86 people consist of men women and children. This means that

x + y + z = 86 - - - - - - - - - - - - 1

There are twice as many women than there are men. It means that

x = y/2

There are 6 more children than there are women. This means that

z = y + 6

Substituting x = y/2 and z = y + 6 into equation 1, it becomes

y/2 + y + y + 6 = 86

multiplying through by 2, it becomes

y + 2y + 2y + 12 = 172

5y = 172 - 12 = 160

y = 160/5 = 32

x = y/2 = 32/2

x = 16

z = y + 6 = 32 + 6

z = 38

8 0
3 years ago
Verify that the given point is on the curve and find the lines that are (a) tangent and (b) normal to the curve at the given poi
lara [203]

For each curve, plug in the given point (x,y) and check if the equality holds. For example:

(I) (2, 3) does lie on x^2+xy-y^2=1 since 2^2 + 2*3 - 3^2 = 4 + 6 - 9 = 1.

For part (a), compute the derivative \frac{\mathrm dy}{\mathrm dx}, and evaluate it for the given point (x,y). This is the slope of the tangent line at the point. For example:

(I) The derivative is

x^2+xy-y^2=1\overset{\frac{\mathrm d}{\mathrm dx}}{\implies}2x+x\dfrac{\mathrm dy}{\mathrm dx}+y-2y\dfrac{\mathrm dy}{\mathrm dx}=0\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x+y}{2y-x}

so the slope of the tangent at (2, 3) is

\dfrac{\mathrm dy}{\mathrm dx}(2,3)=\dfrac74

and its equation is then

y-3=\dfrac74(x-2)\implies y=\dfrac74x-\dfrac12

For part (b), recall that normal lines are perpendicular to tangent lines, so their slopes are negative reciprocals of the slopes of the tangents, -\frac1{\frac{\mathrm dy}{\mathrm dx}}. For example:

(I) The tangent has slope 7/4, so the normal has slope -4/7. Then the normal line has equation

y-3=-\dfrac47(x-2)\implies y=-\dfrac47x+\dfrac{29}7

3 0
3 years ago
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