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2 years ago

Lm=6x+3 mn=4x-17 ln=x+14 (find the range of possible values for x, help a sister out)

Mathematics

1 answer:

katen-ka-za [31]2 years ago

5 0

Answer:

Step-by-step explanation:

lm=6x+3

mn=4x-17

ln=x+14

lm+mn>ln

6x+3+4x-17>x+14

10x-14>x+14

9x>28

x>28/9

mn+ln>lm

4x-17+x+14>6x+3

5x-3>6x+3

-x>6

x<-6

lm+ln>mn

6x+3+x+14>4x-17

7x+17>4x-17

3x>-34

x>-34/3

combining x<-6 or x>28/9

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Help please stuck again .

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If the polygons are similar, then the top side is equal to one half of the left side.
Since side (x -1) = 8, then x = 9.

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2 years ago

How many handshakes are possible at a party of 65 people if everyone shakes hands once?

riadik2000 [5.3K]

You must calculate how many ways can 2 people be selected from 65.
The formula is:
n! / r! * (n-r)! =
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Source:
http://www.1728.org/combinat.htm

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3 years ago

on a large college campus, 84% of the students report drinking alcohol within the past month, 33% report using some type of toba

Natasha_Volkova [10]

Answer: 0.31

Step-by-step explanation:

Let A denotes the event that the students report drinking alcohol and B denotes the students report using some type of tobacco product .

Given : P(A) =0.84 ; P(B)=0.33 and P(A∪B)=0.86

We know that $P(A\cap B)=P(A)+P(B)-P(A\cup B)$

Then, the probability that the student both drunk alcohol and used tobacco in the past month is given by :-

$P(A\cap B)=0.84+0.33-0.86=0.31$

Hence, the probability that the student both drunk alcohol and used tobacco in the past month = 0.31

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2 years ago

Cotθ= tan30° find theta

scoundrel [369]

Answer:

Step-by-step explanation:

Cot is the same as 1/tan so:

$1/tan(theta) = tan(30)$

By rearranging the equation, we get:

$1/tan(30) = tan(theta)$

By taking the inverse tan, we get:

$theta = tan^-1 (1/tan(30)) =60$

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2 years ago

Which real value of m makes the expression undefined<br><br> M^8+1/4m^2

Soloha48 [4]

Answer:

m = 0

Step-by-step explanation:

The denominator of the rational expression cannot be zero as this would make the rational expression undefined. Equating the denominator to zero and solving gives the value that m cannot be.

4m² = 0 ⇒ m² = 0 ⇒ m = 0 ← excluded value

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2 years ago