The initial kick is the first force applied to the ball. It sends the ball up into the air (at some angle). If gravity wasn't present, then the ball would go upward forever in a straight line. However, gravity is the second force pulling down on the ball. This explains why the ball hits some peak point or highest point before it is pulled to the ground. Overall, the path the ball takes is a parabolic arch.
In short, the two forces are the initial kick and gravity.
side note: technically air resistance (aka air friction or drag) is a force being applied since the air pushes against the ball to slow it down, but often air resistance is really complicated and beyond the scope of many math courses. So your teacher may want you to ignore air resistance.
Another note: the initial kick is a one time force that only happens at the beginning. Once the ball is in the air, that force isn't applied anymore. In contrast, the force of gravity is always present and always pulling down. It's probably incredibly obvious, but it's worth pointing out this difference.
Given:
grams of fat : 34 grams TO weight of woman : 102 pounds
grams of fat : ? TO weight of woman : 180 pounds
This is a proportion problem: 34 grams to 102 pounds.
We first have to convert a unit of measure to another to maintain uniformity of measure. let us convert pounds to grams:
102 pounds * 453.592 grams / pound = 46,266.384 grams
180 pounds * 453.592 grams / pound = 81,646.560 grams
34 grams to 46,266.384 grams = x grams to 81,646.560 grams
proportion: a:b = c:d where ad = bc
34 grams * 81,646.560 grams = x * 46,266.384 grams
2,775,983.04 grams² = x * 46,266.384 grams
2,775,983.04 grams² ÷ 46,266.384 grams = x
60 grams = x
A woman weighing 180 pounds should eat 60 grams of fat to maintain her weight.
Answer:
£102.04
Step-by-step explanation:
£1250 - £1100 = £150
printer sold for £150
£150 = 147%
1% = 1.0204
100% = 102.0408
to 2dp = £102.04
-x^2 + 9 - 3x^2 - 11x + 4
-4x^2 - 11x + 13
Answer:
42(79,42,32)
Step-by-step explanation:
I got the solution by using the Trigonometric Identities. If somebody else could do a step by step explanation that would be great.