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BabaBlast [244]
3 years ago
12

How do I write an algebraic expression using words for a - b please respond urgently I need to this

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
7 0

Answer:

integer represented as a minus the integer represented as b

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Solve the following equation for <br><br><br> G:2 (g-h) = b+4
Klio2033 [76]

If the equation 2(g - h) = b + 4 is solved for g. Then the value of g will be b/2 + h + 2.

<h3>What is the solution of the equation?</h3>

A combination of equations solution is a collection of values x, y, z, etc. that enable all of the calculations to true at the same time.

The equation is given below.

2(g - h) = b + 4

Then solve the equation for the value of g. Then we have

2(g - h) = b + 4

   g - h = b/2 + 2

        g = h + b/2 + 2

More about the solution of the equation link is given below.

brainly.com/question/545403

#SPJ1

3 0
2 years ago
How do you solve 4•(4y/3-2) + 3y = 17
Hunter-Best [27]
Us photo math , it show u even the steps of how was it solve
6 0
3 years ago
I need help with part b. I feel like there’s a catch, I want to do the first derivative test, however, I feel like there is a be
Sladkaya [172]

Answer:

The fifth degree Taylor polynomial of g(x) is increasing around x=-1

Step-by-step explanation:

Yes, you can do the derivative of the fifth degree Taylor polynomial, but notice that its derivative evaluated at x =-1 will give zero for all its terms except for the one of first order, so the calculation becomes simple:

P_5(x)=g(-1)+g'(-1)\,(x+1)+g"(-1)\, \frac{(x+1)^2}{2!} +g^{(3)}(-1)\, \frac{(x+1)^3}{3!} + g^{(4)}(-1)\, \frac{(x+1)^4}{4!} +g^{(5)}(-1)\, \frac{(x+1)^5}{5!}

and when you do its derivative:

1) the constant term renders zero,

2) the following term (term of order 1, the linear term) renders: g'(-1)\,(1) since the derivative of (x+1) is one,

3) all other terms will keep at least one factor (x+1) in their derivative, and this evaluated at x = -1 will render zero

Therefore, the only term that would give you something different from zero once evaluated at x = -1 is the derivative of that linear term. and that only non-zero term is: g'(-1)= 7 as per the information given. Therefore, the function has derivative larger than zero, then it is increasing in the vicinity of x = -1

6 0
3 years ago
Determine the mean of the data. Round to the nearest tenth. 6, 9, 15, 22, 30, 36
pshichka [43]
To find the mean you add all the numbers and divide it by the amount of numbers there is so add
6+9+15+22+30+36=118 
there is 6 number so divide 118 by 6
118/6=<span>19.6666666667 rounded to the nearest tenth it would be 20
So your mean would be 20 
let me know if you have any questions</span>
3 0
3 years ago
Find the equation of the line through (2,4) and (3,-1)
Natasha2012 [34]

y=23x+143 hope this helps

3 0
3 years ago
Read 2 more answers
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