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ohaa [14]
3 years ago
8

Answser the question 90+7x(7-1)

Mathematics
1 answer:
Ivanshal [37]3 years ago
4 0

Answer:

582

Step-by-step explanation:

97x6 = 582 trust me i am a math matichion

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HELP ITS MATH AND I SUCK AT MATH WILL GIVE BRAINLIEST :)))))
Snowcat [4.5K]

Answer:

i believe it's A. f(x) slope is greater than g(x) slope

Step-by-step explanation:

the slope of f(x) is -2, while g(x) is -6. you may think "why isn't -6? 6 is bigger, isn't it?" In this case, they're both negative so the number closer to zero is the greater one

3 0
4 years ago
Read 2 more answers
(b) The table below indicates the cost of certain air tel kiosk Z 0.15 0.20 0.25 0.75 0.80 0.85 1.85 1.90 1.95 2.00 2.05 QZ 0.05
marshall27 [118]

Using the normal distribution, it is found that there is a

a) 0% probability that the number of calls received at the switchboard will be exactly 578.

b) 0.1586 = 15.86% probability that the number of calls received at the switchboard will be less than 570.

c) 0.9485 = 94.85% probability that the number of calls received at the switchboard will be between 561 and 600.

<h3>Normal Probability Distribution</h3>

In a <em>normal distribution</em> with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

  • The mean is of 580, hence \mu = 580.
  • The standard deviation is of 10, hence \sigma = 10.

Item a:

In the normal distribution, the probability of an exact value is 0%, hence, 0% probability that the number of calls received at the switchboard will be exactly 578.

Item b:

The probability is the <u>p-value of Z when X = 570</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{570 - 580}{10}

Z = -1

Z = -1 has a p-value of 0.1586.

0.1586 = 15.86% probability that the number of calls received at the switchboard will be less than 570.

Item c:

This probability is the <u>p-value of Z when X = 600 subtracted by the p-value of Z when X = 561</u>, hence:

X = 600:

Z = \frac{X - \mu}{\sigma}

Z = \frac{570 - 580}{10}

Z = 2

Z = 2 has a p-value of 0.9772.

X = 561:

Z = \frac{X - \mu}{\sigma}

Z = \frac{561 - 580}{10}

Z = -1.9

Z = -1.9 has a p-value of 0.0287.

0.9772 - 0.0287 = 0.9485.

0.9485 = 94.85% probability that the number of calls received at the switchboard will be between 561 and 600.

You can learn more about the normal distribution at brainly.com/question/24663213

8 0
2 years ago
A grocery store has an average sales of $8000 per day. The store introduced several advertising campaigns in order to increase s
Ann [662]

Answer:

a) Z= 0.0228

b) based on the critical value, it is a one tailed test

c) Since the p-value is less than the level of significance (α= 0.05) so we reject the null hypothesis.

This implies that the advertising campaign has been effective in increasing sales.

Step-by-step explanation:

The null hypothesis is H₀ : µ = 8000

The alternative hypothesis is H₁ : µ ˃ 8000

Mean (µ) = 8000

Standard deviation (σ) = 1200

n = 64

We will use the Z test to test the hypothesis

Z = (X - µ)/ (σ/√n)

Z = (8300 – 8000)/ (1200/√64)

Z = 300/ (1200/8)

Z = 300/ 150

Z= 2

From the normal distribution table,

2 = 0.4772

Φ(z) = 0.4772

Since Z is positive,

P(x˃a) =0.5 - Φ(z)

= 0.5 – 0.4773

= 0.0228

The required P-value = 0.0228

The P-value of one tail Z test at α= 0.05 level of significance

P-value = p(Z˃2.5)

= 0.0228

Since the p-value is less than the level of significance (α= 0.05) so we reject the null hypothesis.

This implies that the advertising campaign has been effective in increasing sales.

3 0
3 years ago
F(x)=x^3-6/x find the following<br> F(-2)
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Answer:

F=6

Step-by-step explanation:

7+8-9

=6

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1. A

2. C

3. D

4. A

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3 years ago
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