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3 years ago

Can someone please help me ASAP :)

Mathematics

1 answer:

jeyben [28]3 years ago

4 0

Did this a couple years ago, im kinda lost xD . sorry

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This is hard so help meh my teacher just randomly posted this

My name is Ann [436]

Answer:

i don't know uhhhhhhhhhh do what ever you heart says

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3 years ago

How are the points (8,7) and (-8,7) related?

melisa1 [442]

Answer:

The point (-8,7) is the reflection of the point (8,7)

8 0

3 years ago

Select the correct similarity statement.

Nostrana [21]

Answer:

∆STR ~ ∆RTQ

Step-by-step explanation:

For two fugures to be considered similar, it means the corresponding sides are proportional, and as such, the ratio of their corresponding sides are equal.

However, the corresponding angles of two similar figures are the same and equal.

Taking a look at the figure of the triangle given, ∆STR is a right angle triangle, and it is similar to ∆RTQ as the angle formed at <T in ∆RTQ = 90°.

<T in ∆STR = <T in ∆RTQ.

Therefore, the correct similarity statement is ∆STR ~ ∆RTQ.

The last option is correct.

4 0

3 years ago

Which expression is equivalent to [(3xy^-5)^3/(x^-2y^2)^-4]^-2?

Mademuasel [1]

Answer:- a.The given expression is equivalent to $\frac{x^{10}y^{14}}{729}$

Given expression:- $[\frac{(3xy^{-5})^3}{(x^{-2}y^2)^{-4}}]^{-2}$

$=[\frac{(3)^3x^3y^{-5\times3}}{x^{-2\times-4}y^{2\times-4}}]^{-2}.........(a^m)^n=a^{mn}$

$=[\frac{27x^3y^{-15}}{x^8y^{-8}}]^{-2}$

$=[27x^{3-8}y^{-15-(-8)}]^{-2}............\frac{a^m}{a^n}=a^{m-n}$

$=[27x^{-5}y^{-7}]^{-2}=(27)^{-2}(x^{-5})^{-2}(y^{-7})^{-2}.........(a^m)^n=a^{mn}$

$=\frac{1}{(27)^2}(x^{10}y^{14})=\frac{x^{10}y^{14}}{729}$

Thus a. is the right answer.

6 0

3 years ago

Read 2 more answers

Find the work done in emptying a cylindrical tank filled with water. The water is being pumped out from the 6 top. The tank has

lutik1710 [3]

Answer:

908360.67 lb-ft

Step-by-step explanation:

height of tank= 6 ft

diameter of the tank = 4 ft

density of water p = 62.4 lbs/ft

A is the cross sectional area of the tank

A = $\pi r^{2}$

where r = diameter/2 = 4/2 = 2 ft

A = 3.142 x $2^{2}$ = 12.568 ft^2

work done = force x distance through which force is moved

work = F x d

Force due to the water = pgAh

where g = acceleration due to gravity = 32.174 ft/s^2

Force = 62.4 x 32.174 x 12.568 x 6 = 151393.44 lb

work done = force x distance moved

work = 151393.44 x 6 = 908360.67 lb-ft

8 0

3 years ago