Question

Given that QT is and altitude of triangle QRS and that m

Answer 1

Answer:

$RS=15$

Step-by-step explanation:

We have been given a triangle. We are asked to find the measure of segment RS.

Since QT is altitude of our given triangle, so angle QTR and angle QTS are right triangles.

Let us solve for x by equating measure of angle STQ with 90 degrees.

$m\angle STQ=90$

$7x+55=90$

$7x+55-55=90-55$

$7x=35$

$\frac{7x}{7}=\frac{35}{7}$

$x=5$

We can see that segment RS is RT plus TS.

$RS=RT+TS$

$RS=x+1+2x-1$

$RS=x+2x$

$RS=3x$

Upon substituting $x=5$, we will get:

$RS=3*5$

$RS=15$

Therefore, the length of segment RS is 15 units.

Answer 2

Hello from MrBillDoesMath!

Answer:

15

Discussion:

Given: measure angle STQ = 7x + 55.  But, as shown, STQ is a right angle so

7x + 55 = 90          => subtract 55 from each side

7x = 90 -55 = 35   => divide each side by 7

x = 35/7 = 5

Since RS = (x+1)    + (2x-1)  where x = 5.

     RS = (5 + 1) + (2*5 -1)

           = 6         + 9

           = 15

I don't know what choice the answer is as your diagram only shows Choice A

Thank you,

MrB