All categories

2 years ago

Penicillin-binding protein 2a, encoded by the medA gene, isn’t affected by beta-lactam antibiotics.

Biology

1 answer:

Flauer [41]2 years ago

7 0

Answer:

The correct answer is - false.

Explanation:

Penicillin-binding protein 2a or PBPs are protein produced by bacteria that binds with the β-lactam antibiotics such as penicillin. They play role in the cell wall synthesis of bacteria by producing peptidoglycan by catalyzing the reaction.

β-Lactam antibiotics bind with the PBPs and cause the disruption to peptidoglycan cross-linking in the biosynthesis of the cell wall and ultimately lysis of bacteria takes place and cell death.

You might be interested in

Check out this app! It's millions of students helping each other get through their schoolwork. https://brainly.app.link/qpzV02Ma

ivolga24 [154]

Answer:

Its this app only and what your question sir ?

8 0

2 years ago

Read 2 more answers

What are organisms?

IRISSAK [1]

I'd say D but i'm not 100% sure

8 0

3 years ago

Read 2 more answers

Considering the same population of cats as in Part A, what is the expected frequency of each genotype (TLTL, TLTS, TSTS ) based

zaharov [31]

Answer:

P = f(TLTL) = 0,16

H = f(TLTS) = 0,48

Q = f(TSTS) = 0,36

Explanation:

Hello!

The allele proportion of any locus defines the genetic constitution of a population. Its sum is 1 and its values can vary between 0 (absent allele) and 1 (fixed allele).

The calculation of allelic frequencies of a population is made taking into account that homozygotes have two identical alleles and heterozygotes have two different alleles.

In this case, let's say:

f(TL) = p

f(TS) = q

p + q = 1

Considering the genotypes TLTL, TLTS, TSTS, and the allele frequencies:

TL= 0,4

TS= 0,6

Genotypic frequency is the relative proportion of genotypes in a population for the locus in question, that is, the number of times the genotype appears in a population.

P = f(TLTL)

H = f(TLTS)

Q = f(TSTS)

Also P + H + Q = 1

And using the equation for Hardy-Weinberg equilibrium, the genotypic frequencies of equilibrium are given by the development of the binomial:

$p^{2} = f(TLTL)$

$2pq = f(TSTL)$

$q^{2} = f(TSTS)$

So, if the population is in balance:

$P = p^{2}$

$H = 2pq$

$Q = q^{2}$

Replacing the given values of allele frecuencies in each equiation you can calculate the expected frequency of each genotype for the next generation as:

$f(TLTL) = P = p^{2} = 0,4^{2} = 0,16$