Answer:
Is there and multiple choice options?
Explanation:
Answer:
bb would be the phenotype white fur
Explanation:
B is dominant over b. It takes two recessive alleles to produce the phenotype of white fur.
Answer:
You would need to add new enzyme.
Explanation:
The irreversible inhibitor permanently renders the enzyme inactive, so the only way would be to add more enzyme.
Germination I think that it’s
0:3:1
Explanation:
Tasters have the dominant allele for the itter taste of PTC, they can be homozygous TT and heterozygous Tt.
Non-tasters are supposed as autosomal recessive characters
they are homozygous recessive tt when expressed
Given in the equation two heterozygotes parents would produce offspring with the trait in the following ratio.
Tt (parent 1)
Tt (parent 2)
If a punnet square is made
T t
T TT Tt
t Tt tt
The phenotypic character is in the ratio of 0:3:1
There will be 25% chances of recessive trait of non-tasters in the progeny of heterozygous parents.
