3 years ago

Simplify i^7/i x i^3 A. i^4 B.i^11 C.i^3 D. 1

2 answers:

Liula [17]3 years ago

5 0

Answer:

c.i^ 3

Step-by-step explanation:

i^7/i x i^3

i ^ 7 / i ^ 4

i^ 7 - 4

i^ 3

5 0

I got -i in general, but it can be D

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