Answer:
We must solve 3/5 x 3/5.
3/5 x 3/5 = 0.36
The units we'll use is because units are the unt we're given, and it is squared because it is the area of a shape.
Your final answer is 0.36
1. n^2 -8n +16 = 25
Subtract 25 from both sides
n^2 - 8n + 16 - 25 = 0
Simplify
n^2 - 8n - 9 =0
Factor
(n-9)(n+1) = 0
Solve for n
n-9 = 0, n = 9
n+1 = 0, n = -1
Solution: 9,-1
2. C = b^2/25
Multiply both sides by 25:
25c = b^2
Take square root of both sides
b = +/-√25c
Simplify:
b = 5√C, -5√C
3. d = 16t^2 +12t
subtract d from both side:
16t^2 + 12t -d =0
Use quadratic formula to solve:
t = (3 +/-√(9-4d))/8
4. 5w^2 +10w =40
Subtract 40 from both side:
5w^2 + 10w -40 = 0
Factor:
5(w-2)(w+4)=0
Divide both sides by 5:
(w-2)(w+4)=0
Solve for w:
w-2 = 0, w = 2
w+4=0, w = -4
Solution: 2,-4
Convert to equivalent fractions to see
Both bottom s can be 6
So times the half by 3
And times the third by 2
1/2=3/6
1/3=2/6
So she has a total of 5/6 of the movie accounted for...
So the left over is 1/6
1/6 at nighttime
(f/g)(x) = f(x)/g(x)
So the answer is C
I hope it will help
Solution :
To claim to be tested is whether "the mean salary is higher than 48,734".
i.e. μ > 48,734
Therefore the null and the alternative hypothesis are
and 
Here, n = 50
s = 3600
We take , α = 0.05
The test statistics t is given by
t = 2.15
Now the ">" sign in the 
sign indicates that the right tailed test
Now degree of freedom, df = n - 1
= 50 - 1
= 49
Therefore, the p value = 0.02
The observed p value is less than α = 0.05, therefore we reject 
. Hence the mean salary that the accounting graduates are offered from the university is more than the average salary of 48,734 dollar.
