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garri49 [273]
3 years ago
14

8^1/3 dived by 5^-2 Please help

Mathematics
1 answer:
bezimeni [28]3 years ago
8 0

Answer:

50

Step-by-step explanation:

(8^1/3) /(5^-2)

(2)/(0.04)

50

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Devy likes to learn! Could someone please tell me how to answer this question?
Ronch [10]

Answer:

B

Step-by-step explanation:

Recall that if two functions, <em>f</em> and <em>g</em>, are inverses, then by definition:

\displaystyle f(g(x)) = g(f(x)) = x

Hence, the graph of f(g(x)) should be simply <em>y</em> = <em>x</em>.

Therefore, our answer is B, as both coordinates are equivalent for all three points.

4 0
3 years ago
A class votes for their class President Kennedy receives 21 votes which is 6% of the vote what is the total number of students w
Katarina [22]

Answer:

21

Step-by-step explanation:

literally says it in the text ight

6 0
3 years ago
Read 2 more answers
What is negative 21/9 times negative 18/7
diamong [38]

Answer:

negative 21/9 times negative 18/7  is 6

Step-by-step explanation:

The phrase negative 21/9 times negative 18/7 can be written mathematically as

-\frac{21}{9} \times -\frac{18}{7}

Lets first convert the fractions into decimal values

-\frac{21}{9} = -2.33

-\frac{18}{7} =  -2.57

Now on simplyfying

=>-2.33 \times -2.57

=> 5.988

=>6 (rounding off)

We will get a positive value because the multiplicative law states that the product of two negative number is positive

5 0
3 years ago
Two years of local Internet service cost $685, including the installation fee of $85. What is the monthly fee?
AnnZ [28]
685-85=600
1 year =12 months 
12 multiply by 2 =24
600 divided by 24=25
answer=25

8 0
3 years ago
Read 2 more answers
Follow the directions to solve the system of equations by elimination.
Ber [7]
8x + 7y = 39
4x - 14y = -68

(multiply each term in second equation by -2)

8x + 7y = 39
-8x + 28y = 136

(add both equations)

35y = 175

(divide both sides by 35)

y = 5

(substitute value of y in one of the equations)

8x + 7(5) = 39
8x + 35 = 39
8x = 4
x = 1/2
(x, y) = (1/2, 5)
5 0
3 years ago
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