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2 years ago

8^1/3 dived by 5^-2 Please help

Mathematics

1 answer:

bezimeni [28]2 years ago

8 0

Answer:

Step-by-step explanation:

(8^1/3) /(5^-2)

(2)/(0.04)

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The sun shines at a 30° angle to the ground. To the nearest inch, how long is the shadow cast by a 72-in. tall fence post?

tensa zangetsu [6.8K]

The length of the shadow is 124.7 in

Explanation:

Given:

Angle, θ = 30°

Height of the fence, h = 72 in

Length of the shadow, l = ?

Given:

tan 30° = $\frac{perpendicular}{base} = \frac{height of the fence}{length of the shadow}$

$\frac{1}{\sqrt{3} } = \frac{72}{l} \\\\l = 72\sqrt{3} \\\\l = 124.7 in$

Therefore, the length of the shadow is 124.7 in

5 0

2 years ago

Please explain i will mark brainliesttt!

Sati [7]

Answer:

Answer is given below with explanations.

Step-by-step explanation:

$given \: the \: line \: n \: passes \: through \\ \: ( - 3, - 7.5) \: \: and(2, - 5) \\ the \: equation \: of \: the \: line \: is \\ \frac{y - y1}{y2 - y1} = \frac{x - x1}{x2 - x1} \\ here \: x1 = - 3 \: \: \: y1 = - 7.5 \\ and \: \: x2 = 2 \: \: \: y2 = - 5 \\ \frac{y - ( - 7.5)}{ - 5 - ( - 7.5)} = \frac{x - ( - 3)}{2 - ( - 3)} \\ \frac{y + 7.5}{ - 5 + 7.5} = \frac{x + 3}{2 + 3} \\ \frac{y + 7.5}{2.5} = \frac{x + 3}{5} \\ dividing \: by \: 5 \: on \: both \: side s\\ \frac{y + 7.5}{0.5} = \frac{x + 3}{1} \\ 0.5(x + 3) = y + 7.5 \\ 0.5x + 1.5 = y + 7.5 \\ 0.5x - y - 6 = 0 \\ is \: the \: required \: equation.$

HAVE A NICE DAY!

THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION. 

5 0

3 years ago

Please help Question: 6b = 18 Answer: ?

ratelena [41]

Answer:

6b=18

b=18/6

b=3

3 0

2 years ago

Read 2 more answers

TIMED QUESTION NEED HELP FASTWhat values of b satisfy 3(2b + 3)2 = 36?

egoroff_w [7]

Answer:

$\frac{-3+ 2\sqrt{3}}{2}\textrm{ and }\frac{-3- 2\sqrt{3}}{2}$

Step-by-step explanation:

$3(2b+3)^{2}=36\\\frac{3(2b+3)^{2}}{3}=\frac{36}{3}\\(2b+3)^{2}=12$

Taking square root both sides, we get

$\sqrt{(2b+3)^{2}}=\pm \sqrt{12}\\2b+3=\pm \sqrt{4\times 3}\\2b+3=\pm 2\sqrt{3}\\2b+3-3=\pm 2\sqrt{3}-3\\2b=-3\pm 2\sqrt{3}\\b=\frac{-3\pm 2\sqrt{3}}{2}\\b=\frac{-3+ 2\sqrt{3}}{2}\textrm{ or }b=\frac{-3- 2\sqrt{3}}{2}$