1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
postnew [5]
3 years ago
6

Kali and Ryan are selling cheesecakes for a school fundraiser. Customers can buy New York style cheesecakes and apple cheesecake

s. Kali sold 12 New York style cheesecakes and 1 apple cheesecake for a total of $79. Ryan sold 14 New York style cheesecakes and 1 apple cheesecake for a total of $91. Find the cost each of one New York style cheesecake and one apple cheesecake.
Mathematics
1 answer:
valentina_108 [34]3 years ago
8 0

Answer:

New York style cheesecake: $6           Apple cheese cake: $7

Step-by-step explanation:

Ryan and Kali sold the same amount of apple cheesecakes which means the New York cheesecakes differed in amount. Ryan sold 2 more than Kali so the difference in amount would be the cost of 2 New York cheese cakes.

Ryan made $91 and Kali made $79. Since they sold the same amount of apple cheesecakes, we can use their difference in money made to find the cost of 2 New York cheesecakes. So take away 79 from 91 and you get 12. $12 is the price of 2 New York cheesecakes. So take the 12 and divide it by 2. You get 6. $6 is the price of one New York cheesecake.

To find the amount of one apple cheesecake, you just need to multiply the amount of New York cheesecakes Kali sold by the price of 1 New York cheesecake. So 6 multiplied by 12 is equal to 72. Take the money Kali made and take away 72 from it. You get 7. 7 is the cost for one apple cheesecake. $7 for 1 cheesecake.

<em>I hope this helps!</em>

You might be interested in
Find the volume of this figure to the nearest whole number. Use 3.14 for pi.
sukhopar [10]

Answer:

≈ 1800 mm³

Step-by-step explanation:

Volume of the figure above will be given by the formula

Cross section area × length

In this case;

Cross section area will be;

Area of the square + area of the two semi circles

12× 12 + 2(3.14 × 6 ×6/2)

= 144 + 3.14 ×36

= 257.04 mm²

Volume = Cross section area × Length

             = 257.04 × 7

             = 1799.28 mm³

           <u> ≈ 1800 mm³</u>

3 0
3 years ago
I need help please someone help
artcher [175]

Answer:

your answer would be y=3x+3

Step-by-step explanation:

3 0
3 years ago
Order the relative frequencies from least to greatest
Lostsunrise [7]

Answer:

3rd, 1st, 2nd

Step-by-step explanation:

So first rectangle says clay pieces entered by art 3 kids:  relative freq there is 20/88  approx .23

The second rectangle says all painted by art 1 kids:  43/103 approx .42

Third rectangle says art 2 kids who did digital pieces: 24/109 approx .22

Lowest: third rectangle

Medium: first rectangle

Highest: second rectangle

7 0
3 years ago
Hey guys! Okay so this question is kinda hard so if anyone could help that would be great ^-^
Marat540 [252]
There are 3 puppies that are male

2 puppies that are white females

There are 2 puppies that are male, white or both.

The probability that a puppy will be male, white or both is 2/7

hope this helps!
7 0
3 years ago
Calculate the probability that a particle in a one-dimensional box of length aa is found between 0.29a0.29a and 0.34a0.34a when
Helga [31]

Answer:

P(0.29a < X < 0.34a) = -(4a/π) [(cos 0.34πa²) - (cos 0.29πa²)]

Assuming the box is of unit length, a = 1,

0.29a = 0.29 and 0.34a = 0.34

P(0.29 < X < 0.34) = (-4/π) [(cos 0.34π) - (cos 0.29π)] = 0.167 = 0.17 to 2 s.f

Step-by-step explanation:

ψ(x) = 2a(√sin(πxa)

The probability of finding a particle in a specific position for a given energy level in a one-dimensional box is related to the square of the wavefunction

The probability of finding a particle between two points 0.29a and 0.34a is given mathematically as

P(0.29a < X < 0.34a) = ∫⁰•³⁴ᵃ₀.₂₉ₐ ψ²(x) dx

That is, integrating from 0.29a to 0.34a

ψ²(x) = [2a(√sin(πxa)]² = 4a² sin(πxa)

∫⁰•³⁴ᵃ₀.₂₉ₐ ψ²(x) dx = ∫⁰•³⁴ᵃ₀.₂₉ₐ (4a² sin(πxa)) dx

∫⁰•³⁴ᵃ₀.₂₉ₐ (4a² sin(πxa))

= - [(4a²/πa)cos(πxa)]⁰•³⁴ᵃ₀.₂₉ₐ

- [(4a/π)cos(πxa)]⁰•³⁴ᵃ₀.₂₉ₐ = -(4a/π) [(cos 0.34πa²) - (cos 0.29πa²)]

P(0.29a < X < 0.34a) = -(4a/π) [(cos 0.34πa²) - (cos 0.29πa²)]

Assuming the box is of unit length, a = 1

P(0.29 < X < 0.34) = (-4/π) [(cos 0.34π) - (cos 0.29π)] = (-1.273) [0.482 - 0.613] = 0.167.

7 0
4 years ago
Other questions:
  • How do I solve the second question?
    5·1 answer
  • 2y + 2 = -3x
    9·2 answers
  • What is it like to live under a carpet
    9·2 answers
  • Please help i will mark brainliest
    9·2 answers
  • The band at Hawthorne Middle School consists of students in the sixth, seventh, and eighth grades. Student participation in the
    8·2 answers
  • 32.8519 rounded to the nest hundredth
    5·2 answers
  • According to the rational root theorem, which is a factor of the polynomial f(x)=3x^3-5x^2-12x+20?
    13·1 answer
  • You have a rock with a volume of 15 cm3 and a mass of 45 g. What's its density?
    13·2 answers
  • Helppppppppopp asappppppppp
    11·1 answer
  • If "x" is equal to 6, what is the value of the following expression? y = 2x + 9x + 3
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!