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mart [117]
2 years ago
7

If each quadrilateral below is a rectangle, find the missing measures. ​

Mathematics
1 answer:
sergij07 [2.7K]2 years ago
7 0

Answer:

Recall each angle in a rectangle is 90 degrees.  So to find the other portion, subtract the given angle from the 90 degrees.

Step-by-step explanation:

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20,464,000

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In quadrilateral ABCD, BN and DM are drawn perpendicular to AC such that BN = DM. Prove that O is the midpoint of BD
GaryK [48]

Answer:

Step-by-step explanation:

Given :

In the given quadrilateral ABCD,

BN and DM are the perpendiculars drawn to AC such that,

BN = DM

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Point O is the midpoint of segment BD.

Or

OD = OB

Solution:

In ΔOMD and ΔONB,

∠MOD ≅ NOB [Vertical angles]

∠M ≅ ∠N ≅ 90° [Given]

Therefore, by AA property of similarity,

ΔOMD ~ Δ ONB

Therefore, their corresponding sides will be proportional,

\frac{DM}{BN}=\frac{OD}{OB}

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4 0
4 years ago
Find the smallest zero solution of h(x)= 4x^2-8x-60
Komok [63]
-3.

Multiply 60 with 4 and then find the factor when added together which would give you the middle number. Notice that because it is a negative equation that both signs are negative. This means that the biggest factor of 240 will be negative.

Then, rewrite the equation 4x^2 +12x -20x -60 and divide it into two parts (4x^2 + 12x) (-20x-60) and then factor each part. If done correctly, the numbers left in the parenthesis should be the same. This way the part outside is one factor and the part inside is the other. This should get you 4x -20 and x +3.

Set both equal to zero and you get your two solutions. One is -3 and the other is 5.

Hope this helps!
4 0
4 years ago
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