Using the method of checking each answer to see if it is possible that they are correct.
The 3 in the 350 can also be referred to as just 300 because it a 3 in the hundreds place. Also because if the rest of the numbers following the "3" were zeros the number would be 300.
The 3 in the 403 can be just referred to as 3 because there are no other numbers following it, and the 3 is in the ones place.
A. THE 3 IN 350 IS 10 TIMES THE VALUE OF THE 3 IN 403
-Saying that 300 is ten times greater than 3-
To check that would mean that:
300 = 3x10
300=30
300≠30
ANSWER A DOES NOT WORK BECAUSE 300 DOES NOT EQUAL 30
B: THE 3 IN 350 IS 100 TIMES THE VALUE OF THE<span> 3</span><span> IN 403
</span>-Saying that 300 is one hundred times greater than the 3-
To check that would mean that:
300=3(100)
300=300
ANSWER B WORKS AND IS THE CORRECT ANSWER BECAUSE 300=300
C: THE 3 IN 403 IS 10 TIMES THE VALUE OF THE 3 IN 350
-Saying that the 3 in ten times greater than the value of 300-
To check that would mean that:
3=300x10
3=3000
3≠3000
ANSWER C DOES NOT WORK BECAUSE 3 IS NOT EQUAL TO 3000
<span>D: THE 3 IN 403 IS 100 TIMES THE VALUE OF THE 3 IN 350
-Saying that 3 is one hundred times greater than 300-
To check that would mean that:
3=300(100)
3=30000
3</span>≠30000
ANSWER D DOES NOT WORK BECAUSE 3 IS NOT EQUAL TO 30000
THE CORRECT ANSWER IS B
Answer:
y=-1x^2 -4x +5
Step-by-step explanation:
Given points (-2, 9), (-4, 5), and (1, 0)
General quadratic equation is y=ax^2 +bx+c
plug in each point and frame three equations
(-2,9)
equation 1
(-4,5)
5 = 16a -4b+c equation 2
(1,0)
0= a + b + c equation 3
Use equation 1 and 3
multiply third equation by -1 and then add it with equation 1
4a - 2a + c = 9
-a -b -c = 0
---------------------
3a - 3b = 9
divide whole equation by 3
a - b = 3 equation 4
use equation 2 and 3
16a -4b+c = 5
-a -b -c =0
------------------------
15a -5b = 5
divide whole equation by 5
3a -b= 1 equation 5
use equation 4 and 5 . multiply equation 5 by -1
-3a +b =-1
a - b = 3
-----------------------
-2a = 2
a= -1
plug it in equation 4 and find out b
a - b = 3
-1 - b = 3
add 1 on both sides
-b = 4 so b= -4
Now plug in the values and find out c
a + b+c = 0
-1 -4 + c= 0
-5 +c =0
c=5
Now plug in the values in the general equation
y=ax^2 +bx+c
y=-1x^2 -4x +5
Answer:
y=98
Step-by-step explanation:
Hello from MrBillDoesMath!
Answer:
Choice D.
Discussion:
Substitute x = 9 in the choices
A. when x = 9, x^2 - 6x + 9 = 36
B. when x = 9, x^2 + 16x + 63 = 288
C. when x = 9, x^2 + 14x + 45 = 252
D. when x = 9, x^2 -12x + 27 = 0
Thank you,
MrB
