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olga nikolaevna [1]
3 years ago
5

Un lote de 250 pijamas tiene un de 20.000, ¿cuál es el costo de cada pijama?​

Chemistry
1 answer:
zysi [14]3 years ago
6 0
Answer in file below

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The electron config for 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f14 5d10 6p3​
nadya68 [22]

Answer:

I don't understand what you are asking

3 0
3 years ago
A stock solution of ammonia in water is 28 wt% NH3. The Formal Weight (FW) of NH3 is 17.03 g/mol). The solution density at room
weqwewe [10]

Answer:

[NH₃] = 14.7 mol/L

Explanation:

28 wt% is a type of concentration that indicates that 28 g of ammonia is contained in 100 g of solution.

Let's determine the amount of ammonia:

28 g . 1 mol / 17.03g = 1.64 moles of NH₃

You need to consider that, when you have density's data it is always referred to solution:

Mass of solution is 100 g, let's find out the volume

0.90 g/mL = 100 g /V

V = 100 g / 0.90mL/g → 111.1 mL

We convert the volume to L → 111.1 mL . 1 L/1000mL = 0.1111 L

mol/L = 1.64 mol/0.1111L → 14.7 M

mol/L = M → molarity a sort of concentration that indicates the moles of solute in 1L of solution

4 0
2 years ago
Match the characteristics and elements to their group.
Luba_88 [7]

Answer:

Kr is a Noble Gas. Na is an alkali metal. F is halogen.

Group 17 is halogens. Inert is Noble Gases. Odourless and colourless is Noble Gases. Alkali metals do not occur freely in nature. Alkali metals are malleable

Explanation:

8 0
2 years ago
I would appreciate some help if anyone can.
stiks02 [169]

the second option is the correct answer i PROMISE

5 0
3 years ago
When 21.5 g of CH4 gas reacts with 387.5 g O2 gas, how much CO2 is formed?
Doss [256]

Answer:

Mass = 58.96 g

Explanation:

Given data:

Mass of CH₄ = 21.5 g

Mass of O₂ = 387.5 g

Mass of CO₂ formed = ?

Solution:

Chemical equation:

CH₄ + 2O₂       →   CO₂ +  2H₂O

Number of moles of CH₄:

Number of moles = mass / molar mass

Number of moles = 21.5 g/ 16 g/mol

Number of moles = 1.34 mol

Number of moles of O₂ :

Number of moles = mass / molar mass

Number of moles = 387.5 g/ 32 g/mol

Number of moles = 12.1 mol

now we will compare the moles of CO₂  with O₂  and CH₄.

                       O₂             :          CO₂

                          2             :            1

                          12.1          :          1/2×12.1 = 6.05 mol

                        CH₄          :          CO₂

                           1              :            1

                          1.34           :         1.34

Number of moles of CO₂ produced by  CH₄ are less thus it will limiting reactant.

Mass of  CO₂:

Mass = number of moles × molar mass

Mass =  1.34 mol × 44 g/mol

Mass = 58.96 g

8 0
3 years ago
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