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Semmy [17]
3 years ago
7

Which choice names part of the lithosphere?

Chemistry
1 answer:
9966 [12]3 years ago
6 0
The lithosphere is the solid, outer part is the earth it includes the brittle upper portion of the mantle and the crust and the outermost layers of Earths structures
You might be interested in
Method A: Does not transfer heat through solids and requires a medium for heat transfer Method B: Requires a material medium and
Paha777 [63]

Method A is Convection

Method B is Conduction

Explanation:

From the problem, we can infer that method A is convection and method B is conduction.

Conduction, convection and radiation are the three main methods of heat transfer.

  • Conduction and convection requires material medium to propagate.
  • Radiation occurs in the absence of a material medium.
  • Conduction mostly occurs in solid. Here, heat is transferred from one hot end to the cold end of the solid. The vibration of the particles in the hot end causes the transfer of kinetic energy to the cold end until thermal equilibrium is reached.
  • In convection, heat is primarily transferred in fluids as a result of density differences. Convection involves the motion of the materials of the medium. Hot air is light and it rises whereas cold air is dense and it sinks.

Learn more:

Sun brainly.com/question/1140127

#learnwithBrainly

6 0
3 years ago
What mass (g) of AgBr is formed when 41.8 mL of 0.152 M AgNO3 is treated with an excess of aqueous hydrobromic acid?
jok3333 [9.3K]

Answer:

m AgBr = 1.193 g

Explanation:

  • AgNO3 + HBr → AgBr + HNO3

∴ V AgNO3 = 41.8 mL = 0.0418 L

∴ [ AgNO3 ] = 0.152 mol/L

∴ Mw AgBr = 187.77 g/mol

⇒ n AgNO3 = (0.0418 L)(0.152 mol/L) = 6.3536 E-3 mol AgNO3

⇒ n AgBr = (6.3536 E-3 mol AgNO3)(mol AgBr/mol AgNO3) = 6.3536 E-3 mol AgBr

⇒ m AgBr =  (6.3536 E-3 mol AgBr)(187.77 g/mol) = 1.193 g AgBr

8 0
3 years ago
If 10.4 grams of iron metal react with 28.4 grams of silver nitrate, how many grams of iron nitrate can be formed and how many g
Trava [24]

Answer:

71.1

Explanation:

1 mol Fe = 10.4 g/55.85 g/mol = 0.186

1 mol AgNo3 = 28.4 g/169.87 g/mol = 0.178 mol AgNo3

then since Ag:Fe is 1:3, AgNo3 is the limiting reactant

So now

0.178 moles * 1/3 * 241.83 g/mol Fe(NO3)3 = 14.35 g Fe(NO3)3

Excess reactant: 0.178 moes AgNO3 * 1/3 = 0.059

0.186 - 0.059 = 0.127 moles Fe * 55.85 g/mol Fe = 7.1 g Fe excess

8 0
3 years ago
Which one of the following reactions would produce t-butyl methyl ether in high yield?
swat32

Answer:

D) sodium t-butoxide + bromomethane

Explanation:

The alkoxide ion is a strong nucleophile, that unlike alcohols, will react with primary alkyl halides to form ether. This general reaction is known as <em>the Williamson synthesis</em>, and is a SN₂ displacement. The alkyl halide must be primary so the back side attack is not hindered, and the alkoxide ion must be formed with the most hindered group.

The mechanism can be seen in the attachment.

7 0
4 years ago
Determine the number of atoms present in 2 moles of argon gas
Reptile [31]
2 moles x 6.02 x 10^23 maybe
4 0
3 years ago
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