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2 years ago

Which choice names part of the lithosphere?

1 answer:

6 0

The lithosphere is the solid, outer part is the earth it includes the brittle upper portion of the mantle and the crust and the outermost layers of Earths structures

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From where do the gems used in Jewlery come? A. they are mettallic ore B.they are nonmettallic silicates C. they are mettallic m

mixas84 [53]

The answer is D, because gems are usually not mettallic

6 0

3 years ago

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2) A common "rule of thumb" -- for many reactions around room temperature is that the

babunello [35]

The question is incomplete. The complete question is :

A common "rule of thumb" for many reactions around room temperature is that the rate will double for each ten degree increase in temperature. Does the reaction you have studied seem to obey this rule? (Hint: Use your activation energy to calculate the ratio of rate constants at 300 and 310 Kelvin.)

Solutions :

If we consider the activation energy to be constant for the increase in 10 K temperature. (i.e. 300 K → 310 K), then the rate of the reaction will increase. This happens because of the change in the rate constant that leads to the change in overall rate of reaction.

Let's take :

$T_1=300 \ K$

$T_2=310 \ K$

The rate constant = $K_1 \text{ and } K_2$ respectively.

The activation energy and the Arhenius factor is same.

So by the arhenius equation,

$K_1 = Ae^{-\frac{E_a}{RT_1}}$ and $K_2 = Ae^{-\frac{E_a}{RT_2}}$

$\Rightarrow \frac{K_1}{K_2}= \frac{e^{-\frac{E_a}{RT_1}}}{e^{-\frac{E_a}{RT_2}}}$

$\Rightarrow \frac{K_1}{K_2}= e^{-\frac{E_a}{R}\left(\frac{1}{T_1}-\frac{1}{T_2}\right)}$

$\Rightarrow \ln \frac{K_1}{K_2}= - \frac{E_a}{R} \left(\frac{1}{T_1} -\frac{1}{T_2} \right)$

$\Rightarrow \ln \frac{K_2}{K_1}= \frac{E_a}{R} \left(\frac{1}{T_1} -\frac{1}{T_2} \right)$

Given, $E_a = 0.269$ J/mol

R = 8.314 J/mol/K

$\Rightarrow \ln \frac{K_2}{K_1}= \frac{0.269}{8.314} \left(\frac{1}{300} -\frac{1}{310} \right)$

$\Rightarrow \ln \frac{K_2}{K_1}= \frac{0.269}{8.314} \times \frac{10}{300 \times 310}$

$\Rightarrow \ln \frac{K_2}{K_1}= 3.479 \times 10^{-6}$

$\Rightarrow \frac{K_2}{K_1}= e^{3.479 \times 10^{-6}}$

$\Rightarrow \frac{K_2}{K_1}= 1$

∴ $K_2=K_1$

So, no this reaction does not seem to follow the thumb rule as its activation energy is very low.

8 0

2 years ago

If I have 21 liters of gas held at a pressure of 78 atm and a temperature of 900 K, what will

shusha [124]

Answer:

30.33L

Explanation:

Using Boyle's law which states that the volume of a given mass of gas is inversely proportional to the pressure, provided temperature remains constant and Charles law states that the volume of a given mass of gas is directly proportional to the temperature provided the pressure remains constant

P1V1/T1 = P2V2/ T2

P1 = 78atm, V1 = 21L , T1 = 900K

P2 = 45atm, V2 = ? , T2 =750K

78× 21 / 900 = 45×V2 / 750

1638/900 = 45 V2 / 750

1638×750 = 900×45V2

1228500 = 40500V2

Divide both sides by 40500

1228500÷40500= V2

V2 = 30.33L

I hope this was helpful, please mark as brainliest

6 0

2 years ago

ХА

kvasek [131]

Answer:

B. Biosphere.

Explanation:

8 0

2 years ago

I WILL MARK YOU BRAINLYEST

Agata [3.3K]

Answer:

Osmosis is the diffusion of ⇒ water across a selectively permeable membrane. This process does not require the cell to use ⇒ energy to move molecules. It is an example of ⇒ passive transport.

Explanation:

3 0

3 years ago

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