1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
olchik [2.2K]
4 years ago
11

A cylinder with a movable piston contains 2.00 g of helium, He, at room temperature. More helium was added to the cylinder and t

he volume was adjusted so that the gas pressure remained the same. How many grams of helium were added to the cylinder if the volume was changed from 2.00 L to 3.70 L ? (The temperature was held constant.)
Chemistry
1 answer:
aliya0001 [1]4 years ago
5 0

Hey There!

Ideal gas equation: PV = nRT where P is pressure, V is volume, n is moles of gas, R is molar gas constant and T is temperature.

Since P, R and T are constant, V/n = constant

V1 = 2.00 L, V2 = 3.30 L

n1 = (2.00 g)/(4.00 g/mol) = 0.5 mol, n2 = ?

V1/n1 = V2/n2

2.00/0.5 = 3.30/n2

n2 = 0.825 mol

Moles of He added = n2 - n1

= 0.825 - 0.5 = 0.325 mol

Mass of He added = moles x atomic mass

= 0.325 * 4.00 = 1.30 g of He

You might be interested in
What two types of elements are ionic compounds made of?
mash [69]

Answer:

ionic compounds are made from metal and non mental elements

Explanation:

in this case it is know as an ionic compound because it contains a charge. For example, NaCl is simply a compound as it contains no charges (the charges cancel out as Cl is -1 and Na is +1)

but OH- is an ionic compound as it has a charge if -1 (O has a -2 charge and H has a +1 charge, so -2+1=-1 so OH has -1 charge)

8 0
3 years ago
If you have 40 grams of potassium nitrate in 100 grams of water at 20 C:
anygoal [31]

Answer:

Explanation:The final homogenous solution, after cooling it to 40°C, will contain 47 g of potassium sulfate disolved in 150 g of water, so you can calculate the amount disolved per 100 g of water in this way:

[47 g of solute / 150 g of water] * 100 g of g of water = 31.33 grams of solute in 100 g of water.

So, when you compare with the solutiblity, 15 g of solute / 100 g of water, you realize that the solution has more solute dissolved with means that it is supersaturated.

To make a saturated solution, 15 grams of potassium sulfate would dissolve in 100 g of water.

Read more on Brainly.com - brainly.com/question/5143785#readmore

7 0
3 years ago
When the pH of a solution changes from a pH of 5 to a pH of 3, the hydronium ion concentration is
gizmo_the_mogwai [7]

Answer : The correct option is, (D) 100 times the original content.

Explanation :

As we are given the pH of the solution change. Now we have to calculate the ratio of the hydronium ion concentration at pH = 5 and pH = 3

As we know that,

pH=-\log [H_3O^+]

The hydronium ion concentration at pH = 5.

5=-\log [H_3O^+]

[H_3O^+]=1\times 10^{-5}M      ..............(1)

The hydronium ion concentration at pH = 3.

3=-\log [H_3O^+]

[H_3O^+]=1\times 10^{-3}M      ................(2)

By dividing the equation 1 and 2 we get the ratio of the hydronium ion concentration.

\frac{[H_3O^+]_{original}}{[H_3O^+]_{final}}=\frac{1\times 10^{-5}}{1\times 10^{-3}}=\frac{1}{100}

100\times [H_3O^+]_{original}=[H_3O^+]_{final}

From this we conclude that when the pH of a solution changes from a pH of 5 to a pH of 3, the hydronium ion concentration is 100 times the original content.

Hence, the correct option is, (D) 100 times the original content.

7 0
3 years ago
Read 2 more answers
An element has an atomic number of 80. How many protons and electrons are in an atom of the element?
Nadya [2.5K]
80 protons,121 Neutrons, and 80 electrons the element is Mercury
6 0
3 years ago
The addition of 250.0 J to 30.0 g of copper initially at 22.0°C will change its temperature to what final value? (Specific heat
WINSTONCH [101]

Answer:

Final temperature = 43.53^{\circ} C

Explanation:

Given that,

Heat added, Q = 250 J

Mass, m = 30 g

Initial temperature, T₁ = 22°C

The Specific heat of Cu= 0.387 J/g °C

We know that, heat added due to the change in temperature is given by :

Q=mc\Delta T\\\\Q=mc(T_2-T_1)\\\\\dfrac{Q}{mc}=(T_2-T_1)\\\\T_2=\dfrac{Q}{mc}+T_1

Put all the values,

T_2=\dfrac{250}{30\times 0.387}+22\\\\=43.53^{\circ} C

So, the final temperature is equal to 43.53^{\circ} C.

8 0
3 years ago
Other questions:
  • Which reaction has a positive δs°? question 6 options:
    7·1 answer
  • What is the pH of a 9.50×10−2 M ammonia solution??
    14·1 answer
  • HELP PLEASE !!!!! which of the following molecules has a bent shape
    12·2 answers
  • Why are environmental factors important to consider when assessing an individual’s health?
    9·2 answers
  • At 40km up in the atmosphere the pressure is 3.8 kPa. I release a balloon with a volume of 30.0
    15·1 answer
  • How many molecules are in 110.86 g of C6H806?
    10·1 answer
  • A reaction happens quickest during:
    5·2 answers
  • The reaction between NO2 and co to produce no and CO2 is thought to occur in two steps:
    6·1 answer
  • PLEASE ANSWER WILL MARK BRAINLIST
    6·1 answer
  • 11. You have 700 grams of AgO. How many moles are present?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!