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3 years ago

On a coordinate plane, points are at (negative 5, 5), (0, 5), (0, negative 1), and (negative 5, negative 1).

Mathematics

2 answers:

cricket20 [7]3 years ago

5 0

Answer:

22 feet

Step-by-step explanation:

s344n2d4d5 [400]3 years ago

5 0

Answer:The guy is correct. its 2021 eduinty

Have a great day!

Step-by-step explanation:

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Please help asap <br>Thank you

vodka [1.7K]

Answer:

k=70

Step-by-step explanation:

two ways to do this

the sum of k+110 has to equal 180, so k=70

52+58+k has to equal 180, so k=70

8 0

3 years ago

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This one and thats it.

4vir4ik [10]

Answer:

you just take the data given and put it on the graph

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3 years ago

Can someone solve this

Brut [27]

Answer:

8 and 17

Step-by-step explanation:

6 0

3 years ago

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Three sets of data are given below. What is the

Tcecarenko [31]

The answer is C. 7
1.) take 8-(-3)
2.) 9-2
3.) 8-0
Then list the number in order least to greatest
-13 7 8
Find the middle number
Get 7

8 0

3 years ago

Consider the function f(x) = x^3 - 7x^2 - 2x + 14

mars1129 [50]

Answer:

There are 3 zeros, which are:

$x=7,\:x=-\sqrt{2},\:x=\sqrt{2}$

Step-by-step explanation:

Given the function

$f\left(x\right)\:=\:x^3\:-\:7x^2\:-\:2x\:+\:14$

To get the zeros of $f(x)$ , set $y$ or $f(x) =0$

$0=x^3-7x^2-2x+14$

$x^3\:-\:7x^2\:-\:2x\:+\:14=\left(x-7\right)\left(x+\sqrt{2}\right)\left(x-\sqrt{2}\right)$

$\left(x-7\right)\left(x+\sqrt{2}\right)\left(x-\sqrt{2}\right)=0$

Using the zero factor principle:

$\mathrm{ \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

$x-7=0\quad \mathrm{or}\quad \:x+\sqrt{2}=0\quad \mathrm{or}\quad \:x-\sqrt{2}=0$

solving

$x-7=0$

$x=7$

$x+\sqrt{2}=0$

$x=-\sqrt{2}$

$x-\sqrt{2}=0$

$x=\sqrt{2}$

Therefore, there are 3 zeros, which are:

$x=7,\:x=-\sqrt{2},\:x=\sqrt{2}$

8 0

3 years ago