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Alina [70]
3 years ago
7

Please answer quick brain list on cludded ​

Mathematics
1 answer:
Anettt [7]3 years ago
4 0

Answer:

(-3,-4)

Step-by-step explanation:

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i'm sorry, I really don't know, but Brainy or wtvr this keeps notifying me to answer a question and it's annoying.

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natima [27]

Answer:

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3 years ago
The sum to infinity of a geometric progression is 125 and the sum of the first two terms is 120. Find common ratio of the geomet
rodikova [14]

Answer:

Good Luck!

Follow Me!

<em>david_201822</em>

Step-by-step explanation:

3 0
3 years ago
I can’t figure out how to use the zeros in the polynomial. Please explain
Temka [501]

Answer:

a) P (x) = (x + 3) (x-1) (x-4)

b) P (x) = (2x + 5) (5x - 4) (x-6)

c) P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2

Step-by-step explanation:

<u>For the question a *</u> you need to find a polynomial of degree 3 with zeros in -3, 1 and 4.

This means that the polynomial P(x) must be zero when x = -3, x = 1 and x = 4.

Then write the polynomial in factored form.

P (x) = (x + 3) (x-1) (x-4)

Note that this polynomial has degree 3 and is zero at x = -3, x = 1 and x = 4.

<u>For question b, do the same procedure</u>.

Degree: 3

Zeros: -5/2, 4/5, 6.

The factors are

x = -\frac{5}{2}\\\\x +\frac{5}{2} = 0\\\\(2x +5) = 0

---------------------------------------

x =\frac{4}{5}\\\\x-\frac{4}{5} = 0\\\\(5x-4) = 0

--------------------------------------

x = 6\\\\(x-6) = 0

--------------------------------------

P (x) = (2x + 5) (5x - 4) (x-6)

<u>Finally for the question c we have</u>

Degree: 5

Zeros: -3, 1, 4, -1

Multiplicity 2 in -1

x = -3\\\\(x-3) = 0

--------------------------------------

x = 1\\\\(x-1) = 0

--------------------------------------

x = 4\\\\(x-4) = 0

----------------------------------------

x = -1\\\\(x + 1) = 0

-----------------------------------------

P (x) = (x-3) (x-1) (x-4) (x + 1) ^ 2

8 0
3 years ago
Jessie works at a car manufacturing plant. One day she installed a total of 46 axles, 2 in each car she worked on. She wants to
shtirl [24]

Answer:

<h2>             23 cars</h2>

Step-by-step explanation:

total number of cars:    x

the total number of axles:    46

and the number of axles  installed per car:   2

2 axles in each car, then total instaled axles:  2•x

2•x = 46

x = 46÷2

x = 23

5 0
3 years ago
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