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Vesna [10]
3 years ago
6

Given: AB=BC, D is the midpoint of AB, and E is the midpoint BC. Prove: AD=BE

Mathematics
2 answers:
sergij07 [2.7K]3 years ago
5 0

Answer:

AD=BE

Step-by-step explanation:

Because AB and BC are equal, their lengths are also equal and also it is an Isosceles triangle. Therefore the midpoint of AB or the half of AB which is either AD or DE are equal. Vice versa for BC. So AD=BE

wel3 years ago
4 0

Answer:

Using mid point theorem, A line segment joining the mid points of the two sides of the triangle, is equal to half the length of the third side.

D and E are the mid points. Hence,

DE=

2

1

AC

DE=

2

1

(6.4)

DE=3.2cm

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\bf ~~~~~~~~~~~~\textit{internal division of a line segment}&#10;\\\\\\&#10;A(-4,-8)\qquad B(11,7)\qquad&#10;\qquad \stackrel{\textit{ratio from A to B}}{3:7}&#10;\\\\\\&#10;\cfrac{A\underline{C}}{\underline{C} B} = \cfrac{3}{7}\implies \cfrac{A}{B} = \cfrac{3}{7}\implies 7A=3B\implies 7(-4,-8)=3(11,7)\\\\[-0.35em]&#10;~\dotfill\\\\&#10;C=\left(\frac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \frac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)\\\\[-0.35em]&#10;~\dotfill


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