Answer:
0.4546
Step-by-step explanation:
nCr = n!/(n-r)!r!
Number of ways of selecting the four defective voltage regulators from 12 = 12C4 = 12!/(12-4)!4! = 12!/8!4! = (12 *11*10*9)/(4*3*2*1)
12C4 = 495 ways
Number of ways of selecting 2 defectives from line 1 = 6C2 * 6C2
6C2 = 6!/(6-2)!2! = 6!/4!2! = (6*5)/(2*1) = 15
6C2 * 6C2 = 15*15 = 225 ways
Probability = Number of possible outcomes/ Number of total outcomes
Probability that exactly 2 of the defective regulators came from line 1 = 225/40.95 = 0.4546
R^m ÷ r^n is equal to r^(m-n).
For example, 2^5 <span>÷ 2^3 = 2^2.
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Is that what you mean?
Hello and Good Morning/Afternoon
<u>Let's take this problem step-by-step</u>:
<u>To find the solution to a system of equation</u>
⇒ <em>must set</em> the equations equal to each other
⇒ and solve
<u>Let's put that into action</u>

- At this point, to make the whole thing equal zero
⇒ either 'x+3' or 'x-3' equals zero
⇒ must find 'x' that satisify either equation

<u>Let's find the corresponding f(x) to each x-value</u>

<u>Therefore the solutions are (3,6) and (-3,18)</u>
<u />
<u>Answer: (3,6), (-3,18)</u>
<u></u>
Hope that helps!
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