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Setler [38]
3 years ago
8

Fill in the blank to factor to write an equivalent expression to 36a - 16. (blank)(9a - 4)

Mathematics
1 answer:
scZoUnD [109]3 years ago
8 0
The answer should be 4.
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Two assembly lines I and II have the same rate of defectives in their production of voltage regulators. Six regulators are sampl
Kamila [148]

Answer:

0.4546

Step-by-step explanation:

nCr = n!/(n-r)!r!

Number of ways of selecting the four defective voltage regulators from 12 =  12C4 = 12!/(12-4)!4! = 12!/8!4! = (12 *11*10*9)/(4*3*2*1)

12C4 =  495 ways

Number of ways of selecting 2 defectives from line 1 = 6C2 * 6C2

6C2 = 6!/(6-2)!2! = 6!/4!2! = (6*5)/(2*1) = 15

6C2 * 6C2 = 15*15 = 225 ways

Probability = Number of possible outcomes/ Number of total outcomes

Probability that exactly 2 of the defective regulators came from line 1 = 225/40.95 = 0.4546

4 0
4 years ago
Find the intercepts of<br> y= 2x -4
Andrews [41]

Answer:

y intercept is -4

x intercept is 2

4 0
3 years ago
Which expression is equivalent to r^m ÷ r^n?
Andre45 [30]
R^m ÷ r^n is equal to r^(m-n). 

For example, 2^5 <span>÷ 2^3 = 2^2.
</span>
Is that what you mean?
7 0
3 years ago
In matrice find the transpose of (1 -3)(-2 4)
Marianna [84]

48 hope that helps

:)

8 0
3 years ago
PLEASE HELP ASAP!!!!!!!!!!!!!!!!!!!!!!
aivan3 [116]

Hello and Good Morning/Afternoon

<u>Let's take this problem step-by-step</u>:

<u>To find the solution to a system of equation</u>

  ⇒ <em>must set</em> the equations equal to each other

     ⇒ and solve

<u>Let's put that into action</u>

  x^2-2x+3 = -2x + 12\\x^2-2x+2x+3-12=0\\x^2-9=0\\(x+3)(x-3)=0

  • At this point, to make the whole thing equal zero

          ⇒ either 'x+3' or 'x-3' equals zero

              ⇒ must find 'x' that satisify either equation

                    x-3=0\\x=3\\\\x+3=0\\x=-3

<u>Let's find the corresponding f(x) to each x-value</u>

  f(3) = -2(3)+12=-6+12 = 6\\\\f(-3) = -2(-3) + 12=6+12=18

<u>Therefore the solutions are (3,6) and (-3,18)</u>

<u />

<u>Answer: (3,6), (-3,18)</u>

<u></u>

Hope that helps!

#LearnwithBrainly    

3 0
2 years ago
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