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3 years ago

Which law best describes this behavior of gases in the Sun?

Physics

1 answer:

Anvisha [2.4K]3 years ago

7 0

Answer:

The extreme pressure from the weight of the gases that make up the Sun raises the temperature of the core enough for the nuclear reactions to take place, Which law best describes this behavior of gases in the Sun? A. Charles law.

Explanation:

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What is the velocity of an 500- kilogram elevator that has 4000 joules of energy

vlada-n [284]

$\frac{1}{2}$ (500kg) × $v^{2}$ = 4000J

V = √(4000 ÷ 250) = 4 m/s

8 0

4 years ago

g If you keep the launch angle fixed, but double the initial launch speed, what happens to the range?

kiruha [24]

Answer:

Range will become 4 times of initial range

Explanation:

Let the velocity of projection is u

And angle at which projectile is projected is $\Theta$

And acceleration due to gravity is $g\ m/sec^2$

So range of projectile is equal to $R=\frac{u^2sin2\Theta }{g}$ ........eqn 1

Now in second case it is given that velocity of launching is doubled

So new velocity $u_{new}=2u$

So new range will be equal to $R_{new}=\frac{(2u)^2sin2\Theta }{g}=\frac{4u^2sin2\Theta }{g}$ .....eqn 2

Now dividing eqn 2 by eqn 1

$\frac{R_{new}}{R}=\frac{4u^2sin2\Theta }{g}\times \frac{g}{u^2sin2\Theta }$

$R_{new}=4R$

So if we double the initial launch speed then range will become 4 times

4 0

4 years ago

What are some properties of transverse waves?

allsm [11]

They send out waves differently and cannot be heard easily

5 0

3 years ago

A wire of cross-sectional area 5.00 106 m2 has a resistance of 1.75 O. What is the resistance of a wire of the same material and

MakcuM [25]

Answer:

the resistance of the second wire is 1 ohm.

Explanation:

Given;

cross sectional area of the first wire, A₁ = 5.00 x 10⁶ m²

resistance of the first wire, R₁ = 1.75 ohms

cross sectional area of the second wire, A₂ = 8.75 x 10⁶ m²

resistance of the second wire, R₂ = ?

The resistance of a wire is given as;

R ∝ $\frac{L}{A}$

Since the length of the two wires is constant

R₁A₁ = R₂A₂

$R_2 = \frac{R_1A_1}{A_2} \\\\R_2 = \frac{1.75\ \times \ 5.00\times 10^6}{8.75\times 10^6} \\\\R_2 = 1 \ ohm$

Therefore, the resistance of the second wire is 1 ohm.

6 0

3 years ago

How much money did congress authorize to be spent on its construction

ser-zykov [4K]

Answer:

20,000

Explanation:

5 0

4 years ago