What are some properties of transverse waves?
1 answer:
You might be interested in
Answer: the angle between the resultant vector and the vector of the 18 pound is 28°
Explanation:
given that data in the question; as its interpreted in the diagram below;
from the cosine rule, we know that;
a² = b² + c² - 2bc
so
(13)² = (6)² + (18)² - (2 × 6 × 18 ) cos∅
169 = 36 + 324 - 216cos∅
169 = 360 - 216cos∅
216cos∅ = 360 - 169
216cos∅ = 191
cos∅ = 0.8842
∅ = cos⁻¹ ( 0.8842 )
∅ = 27.8° ≈ 28° {nearest whole number}
Therefore the angle between the resultant vector and the vector of the 18 pound is 28°
Answer:
The direction will be and the distance 250.75km.
Explanation:
Let's say A is the displacement vector which represents the first 170km and B the one for the next 230km. Then the components of these vector will be:
The vector which point from the origin to the final position of the plane will be R=A+B. We sum components on <em>x </em>and <em>y </em>independetly (vector property):
If is the direction of R then:
⇒
⇒
.
The distance will be given by the magnitud of the vector R:
⇒
.